Have a query? Ask a Tutor!!

Access to best educators and exclusive paper discussions

Offsite Campus Turito Championship

Can’t find what you’re looking for?

Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

Homework- One to One Solutions
Understand concepts to solve better
Get your doubts solved instantly

Physics-

General

Easy

Question

A piece of copper and the other of germanium are cooled from the room temperature to 80 K, then which of the following would be a correct statement

Resistance of each increases
Resistance of each decreases
Resistance of copper increases while that of germanium decreases
Resistance of copper decreases while that of germanium increases

The correct answer is: Resistance of copper decreases while that of germanium increases

Resistance of conductors (Cu) decreases with decrease in temperature while that of semi-conductors (Ge) increases with decrease in temperature

Related Questions to study

Bonding in a germanium crystal (semi- conductor) is

Bonding in a germanium crystal (semi- conductor) is

Physics-General

What is the coordination number of sodium ions in the case of sodium chloride structure

What is the coordination number of sodium ions in the case of sodium chloride structure

Physics-General

The expected energy of the electrons at absolute zero is called

The expected energy of the electrons at absolute zero is called

Physics-General

parallel

If the series limit of Lymen series for Hydrogen atom is equal to the series limit of Balmer series for a hydrogen like atom, then atomic number o this hydrogen like atom will be

If the series limit of Lymen series for Hydrogen atom is equal to the series limit of Balmer series for a hydrogen like atom, then atomic number o this hydrogen like atom will be

Physics-General

Consider an initially pure M gm sample of ^AX, an isotope that has a half life of T hour, what is it’s initial decay rate (N_A= Avogrado No.)

Consider an initially pure M gm sample of ^AX, an isotope that has a half life of T hour, what is it’s initial decay rate (N_A= Avogrado No.)

Physics-General

Nuclear fission can be explained based on

Nuclear fission can be explained based on

Physics-General

parallel

$text If end text c o s invisible function application 25 to the power of ring operator end exponent plus s i n invisible function application 25 to the power of ring operator end exponent equals$ K_t then cos $20 to the power of ring operator end exponent$ equal to

$text If end text c o s invisible function application 25 to the power of ring operator end exponent plus s i n invisible function application 25 to the power of ring operator end exponent equals$ K_t then cos $20 to the power of ring operator end exponent$ equal to

$text If end text c o s to the power of 2 end exponent invisible function application x plus c o s to the power of 4 end exponent invisible function application x equals 1 text , then the value of end text t a n to the power of 4 end exponent invisible function application x plus c o t to the power of 4 end exponent invisible function application x plus t a n to the power of 2 end exponent invisible function application x minus c o t to the power of 2 end exponent invisible function application x text is equal to end text$

$text If end text c o s to the power of 2 end exponent invisible function application x plus c o s to the power of 4 end exponent invisible function application x equals 1 text , then the value of end text t a n to the power of 4 end exponent invisible function application x plus c o t to the power of 4 end exponent invisible function application x plus t a n to the power of 2 end exponent invisible function application x minus c o t to the power of 2 end exponent invisible function application x text is equal to end text$

If cot $theta equals fraction numerator square root of m plus square root of n over denominator square root of m minus square root of n end root end fraction$ ,then $left parenthesis m plus n right parenthesis$ cos $2 theta$ is equal to

If cot $theta equals fraction numerator square root of m plus square root of n over denominator square root of m minus square root of n end root end fraction$ ,then $left parenthesis m plus n right parenthesis$ cos $2 theta$ is equal to

parallel

On bombarding $U to the power of 235 end exponent$ by slow neutrons, 200MeV energy is released. If the power output of atomic reactor is 1.6 MW, then the rate of fission will be

On bombarding $U to the power of 235 end exponent$ by slow neutrons, 200MeV energy is released. If the power output of atomic reactor is 1.6 MW, then the rate of fission will be

Physics-General

if cos $left parenthesis x minus y right parenthesis$ , cos x and cos $left parenthesis x plus y right parenthesis$ are in HP, then cos $x times s e c invisible function application fraction numerator y over denominator 2 end fraction$ is equal to

if cos $left parenthesis x minus y right parenthesis$ , cos x and cos $left parenthesis x plus y right parenthesis$ are in HP, then cos $x times s e c invisible function application fraction numerator y over denominator 2 end fraction$ is equal to

if cot $alpha c o t invisible function application beta equals 2$ , then $fraction numerator c o s invisible function application left parenthesis alpha plus beta right parenthesis over denominator c o s invisible function application left parenthesis alpha minus beta right parenthesis end fraction$ is equal to

if cot $alpha c o t invisible function application beta equals 2$ , then $fraction numerator c o s invisible function application left parenthesis alpha plus beta right parenthesis over denominator c o s invisible function application left parenthesis alpha minus beta right parenthesis end fraction$ is equal to

parallel

Given $blank fraction numerator pi over denominator 2 end fraction less than alpha less than pi$ ,then the expression $square root of fraction numerator 1 minus s i n invisible function application alpha over denominator 1 plus s i n invisible function application alpha end fraction end root plus square root of fraction numerator 1 plus s i n invisible function application alpha over denominator 1 minus s i n invisible function application alpha end fraction end root$ s equal to $blank$

Given $blank fraction numerator pi over denominator 2 end fraction less than alpha less than pi$ ,then the expression $square root of fraction numerator 1 minus s i n invisible function application alpha over denominator 1 plus s i n invisible function application alpha end fraction end root plus square root of fraction numerator 1 plus s i n invisible function application alpha over denominator 1 minus s i n invisible function application alpha end fraction end root$ s equal to $blank$

$text Find the value of end text x text if end text x equals fraction numerator 1 minus 4 s i n invisible function application 10 to the power of ring operator end exponent s i n invisible function application 70 to the power of ring operator end exponent over denominator 2 s i n invisible function application 10 to the power of ring operator end exponent end fraction text . end text$

$text Find the value of end text x text if end text x equals fraction numerator 1 minus 4 s i n invisible function application 10 to the power of ring operator end exponent s i n invisible function application 70 to the power of ring operator end exponent over denominator 2 s i n invisible function application 10 to the power of ring operator end exponent end fraction text . end text$

If |sinx + cosx| = |sinx| + |cosx|, then x belongs to the quadrant

If |sinx + cosx| = |sinx| + |cosx|, then x belongs to the quadrant

parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.