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Physics-

General

Easy

Question

A step up transformer connected to a $220 blank V blank A C$ line is to supply $22 blank k V$ a neon sign in secondary circuit. In primary circuit a fuse wire is connected which is to blow when the current in the secondary circuit exceeds $10 blank m A$ . The turn ratio of the transformer is

50
100
150
200

The correct answer is: 100

$fraction numerator N subscript s end subscript over denominator N subscript p end subscript end fraction equals fraction numerator V subscript s end subscript over denominator V subscript p end subscript end fraction equals fraction numerator 22000 over denominator 220 end fraction equals 100$

Related Questions to study

A short solenoid of length 4 cm, radius 2 cm and 100 turns is placed inside and on the axis of a long solenoid of length 80 cm and 1500 turns. A current of 3 A flows through the short solenoid. The mutual inductance of two solenoids is

A short solenoid of length 4 cm, radius 2 cm and 100 turns is placed inside and on the axis of a long solenoid of length 80 cm and 1500 turns. A current of 3 A flows through the short solenoid. The mutual inductance of two solenoids is

Physics-General

The number of turns in primary coil of a transformer is 20 and the number of turns in the secondary is 10. If the voltage across the primary is 220 V, what is the voltage across the secondary?

The number of turns in primary coil of a transformer is 20 and the number of turns in the secondary is 10. If the voltage across the primary is 220 V, what is the voltage across the secondary?

Physics-General

$I f tan invisible function application fraction numerator pi over denominator 9 end fraction comma blank x blank a n d tan invisible function application fraction numerator 5 pi over denominator 18 end fraction$ are in A.P. and $tan invisible function application fraction numerator pi over denominator 9 end fraction comma blank y blank a n d tan invisible function application fraction numerator 7 pi over denominator 18 end fraction$ are also in A.P., then

$I f tan invisible function application fraction numerator pi over denominator 9 end fraction comma blank x blank a n d tan invisible function application fraction numerator 5 pi over denominator 18 end fraction$ are in A.P. and $tan invisible function application fraction numerator pi over denominator 9 end fraction comma blank y blank a n d tan invisible function application fraction numerator 7 pi over denominator 18 end fraction$ are also in A.P., then

parallel

Sum of all the solutions in $open square brackets 0 comma blank 4 pi close square brackets$ of the equation $tan invisible function application x plus cot invisible function application x plus 1 equals cos invisible function application open parentheses x plus fraction numerator pi over denominator 4 end fraction close parentheses$ is

Sum of all the solutions in $open square brackets 0 comma blank 4 pi close square brackets$ of the equation $tan invisible function application x plus cot invisible function application x plus 1 equals cos invisible function application open parentheses x plus fraction numerator pi over denominator 4 end fraction close parentheses$ is

If $blank open parentheses 1 minus tan invisible function application theta close parentheses open parentheses 1 plus tan invisible function application theta close parentheses sec to the power of 2 end exponent invisible function application theta plus 2 to the power of tan to the power of 2 end exponent invisible function application theta end exponent equals 0 comma$ then the number of values of $theta$ in the interval $left parenthesis negative pi divided by 2 comma blank pi divided by 2 right parenthesis$ are

If $blank open parentheses 1 minus tan invisible function application theta close parentheses open parentheses 1 plus tan invisible function application theta close parentheses sec to the power of 2 end exponent invisible function application theta plus 2 to the power of tan to the power of 2 end exponent invisible function application theta end exponent equals 0 comma$ then the number of values of $theta$ in the interval $left parenthesis negative pi divided by 2 comma blank pi divided by 2 right parenthesis$ are

If $open vertical bar 2 sin invisible function application theta minus c o s e c blank theta close vertical bar greater or equal than 1$ and $theta not equal to fraction numerator n pi over denominator 2 end fraction comma blank n element of I$ , then

If $open vertical bar 2 sin invisible function application theta minus c o s e c blank theta close vertical bar greater or equal than 1$ and $theta not equal to fraction numerator n pi over denominator 2 end fraction comma blank n element of I$ , then

parallel

If $S equals open curly brackets x element of N blank colon 2 plus log subscript 2 end subscript invisible function application square root of x plus 1 end root greater than 1 minus log subscript 1 divided by 2 end subscript invisible function application square root of 4 minus x to the power of 2 end exponent end root close curly brackets comma$ then

If $S equals open curly brackets x element of N blank colon 2 plus log subscript 2 end subscript invisible function application square root of x plus 1 end root greater than 1 minus log subscript 1 divided by 2 end subscript invisible function application square root of 4 minus x to the power of 2 end exponent end root close curly brackets comma$ then

$log subscript 4 end subscript invisible function application 18$ is

$log subscript 4 end subscript invisible function application 18$ is

If $sin invisible function application 6 theta plus sin invisible function application 4 theta plus sin invisible function application 2 theta equals 0 comma$ then $theta blank$ is equal to $blank open parentheses n element of Z close parentheses$

If $sin invisible function application 6 theta plus sin invisible function application 4 theta plus sin invisible function application 2 theta equals 0 comma$ then $theta blank$ is equal to $blank open parentheses n element of Z close parentheses$

parallel

The area of the circle and the area of a regular polygon of $n$ sides and of perimeter equal to that of the circle are in the ratio of

The area of the circle and the area of a regular polygon of $n$ sides and of perimeter equal to that of the circle are in the ratio of

$I f blank x element of open parentheses pi comma fraction numerator 3 pi over denominator 2 end fraction close parentheses comma blank t h e n blank 4 cos to the power of 2 end exponent invisible function application open parentheses fraction numerator pi over denominator 4 end fraction minus fraction numerator x over denominator 2 end fraction close parentheses plus square root of 4 sin to the power of 4 end exponent invisible function application x plus sin to the power of 2 end exponent invisible function application 2 x end root$ is always equal to

$I f blank x element of open parentheses pi comma fraction numerator 3 pi over denominator 2 end fraction close parentheses comma blank t h e n blank 4 cos to the power of 2 end exponent invisible function application open parentheses fraction numerator pi over denominator 4 end fraction minus fraction numerator x over denominator 2 end fraction close parentheses plus square root of 4 sin to the power of 4 end exponent invisible function application x plus sin to the power of 2 end exponent invisible function application 2 x end root$ is always equal to

If $tan invisible function application theta plus sin invisible function application theta equals m blank a n d tan invisible function application theta minus sin invisible function application theta equals n comma$ then

If $tan invisible function application theta plus sin invisible function application theta equals m blank a n d tan invisible function application theta minus sin invisible function application theta equals n comma$ then

parallel

$I f blank x subscript 1 end subscript blank a n d blank x subscript 2 end subscript$ are two distinct roots of the equation $a cos invisible function application x plus b sin invisible function application x equals c comma blank t h e n tan invisible function application fraction numerator x subscript 1 end subscript plus x subscript 2 end subscript over denominator 2 end fraction$ is equal to

$I f blank x subscript 1 end subscript blank a n d blank x subscript 2 end subscript$ are two distinct roots of the equation $a cos invisible function application x plus b sin invisible function application x equals c comma blank t h e n tan invisible function application fraction numerator x subscript 1 end subscript plus x subscript 2 end subscript over denominator 2 end fraction$ is equal to

$I f fraction numerator sin invisible function application open parentheses x plus y close parentheses over denominator sin invisible function application open parentheses x minus y close parentheses end fraction equals fraction numerator a plus b over denominator a minus b end fraction comma blank t h e n fraction numerator tan invisible function application x over denominator tan invisible function application y end fraction blank i s blank e q u a l blank t o$

$I f fraction numerator sin invisible function application open parentheses x plus y close parentheses over denominator sin invisible function application open parentheses x minus y close parentheses end fraction equals fraction numerator a plus b over denominator a minus b end fraction comma blank t h e n fraction numerator tan invisible function application x over denominator tan invisible function application y end fraction blank i s blank e q u a l blank t o$

Which of the following is not the general solution of $2 to the power of cos invisible function application 2 x end exponent plus 1 equals 3.2 to the power of negative sin to the power of 2 end exponent invisible function application x end exponent ?$

Which of the following is not the general solution of $2 to the power of cos invisible function application 2 x end exponent plus 1 equals 3.2 to the power of negative sin to the power of 2 end exponent invisible function application x end exponent ?$

parallel

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