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Physics

Mechanics

Easy

Question

$I n space t h e space f i g u r e space s h o w n space a space p e n d u l u m space h a v i n g space b o b space o f space m a s s space m space equals space 1 space k g space i s space h a n g i n g space f r o m space t h e space r o o f space o f space a space b o x space o f space m a s s space M comma space k e p t space o v e r space a space s m o o t h space h o r i z o n t a l space p l a n e. space B o x space a n d space a space b l o c k space o f space m a s s space m ¢ space i s space c o n n e c t e d space b y space a space l i g h t space s t r i n g space g o i n g space o v e r space a space m a s s l e s s space l i g h t space p u l l e y. space W h e n space s y s t e m space i s space i n space m o t i o n comma space s t r i n g space m a k e s space a n g l e space 370 space f r o m space t h e space v e r t i c a l space a t space e q u i l i b r i u m space w i t h space r e s p e c t space t o space b o x. space F i n d space o u t space t h e space v a l u e space o f space m ¢ space i n space k g$

$m^{`} = 14 k g$
$m^{`} = 10 k g$
$m^{`} = 9 k g$
$m^{`} = 7 k g$

The correct answer is: $m to the power of apostrophe equals 9 space space k g space space$

$table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em rowspacing 3 pt end attributes row cell text Acceleration of the system end text g text tan end text theta end cell row cell therefore space of 1em g tan invisible function application theta equals fraction numerator m to the power of straight prime g over denominator m to the power of straight prime plus m plus m end fraction not stretchy rightwards double arrow 3 over 4 equals fraction numerator m to the power of straight prime over denominator m to the power of straight prime plus m plus M end fraction not stretchy rightwards double arrow m to the power of straight prime equals 9 kg end cell end table$

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