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Physics-

General

Easy

Question

The figure shows a block of mass m placed on a smooth wedge of mass M. Calculate the value of M¢ and tension in the string, so that the block of mass m will move vertically downward with acceleration 10 m/s²
(Take g = 10 m/s²)

the value of M¢ is $\frac{M \cot θ}{1 - \cot θ}$
the value of M¢ $\frac{M \tan θ}{1 - \tan θ}$
the value of tension in the string is $\frac{M g}{\tan θ}$
the value of tension is $\frac{μ g}{\cot θ}$

The correct answer is: the value of M¢ is $fraction numerator M cot invisible function application theta over denominator 1 minus cot invisible function application theta end fraction$

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