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Physics-

General

Easy

Question

The maximum range of a gun on horizontal terrain is $16 blank k m$ . If $g equals 10 blank m divided by s to the power of 2 end exponent$ . What must be the muzzle velocity of the shell

$200 m / s$
$400 m / s$
$100 m / s$
$50 m / s$

The correct answer is: $400 blank m divided by s$

$R subscript m a x end subscript equals fraction numerator u to the power of 2 end exponent over denominator g end fraction equals 16 cross times 10 to the power of 3 end exponent$
$rightwards double arrow u equals 400 m divided by s$

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