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Question

The wing span of an aeroplane is 36 m. If the plane is flaying at 400 kmh to the power of negative 1 end exponent, the emf induced between the wings tips is (assume V equals 4 cross times 10 to the power of negative 5 end exponent blank T right parenthesis

  1. 16 V  
  2. 1.6 V  
  3. 0.16 V  
  4. 0.016 V  

The correct answer is: 0.16 V


    l equals 36 m comma blank v equals 400 blank k m h to the power of negative 1 end exponent
    = fraction numerator 400 cross times 1000 over denominator 60 cross times 60 end fraction equals fraction numerator 100 over denominator 9 end fraction blank m s to the power of negative 1 end exponent
    = V= 4 cross times 10 to the power of negative 5 end exponent T
    e equals B l v equals 4 cross times 10 to the power of negative 5 end exponent cross times 36 cross times fraction numerator 1000 over denominator 9 end fraction equals 0.16V

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