Physics-
General
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Question

Two springs of force constants K and 2K are connected to a mass as shown below. The frequency of oscillation of the mass is 

  1. left parenthesis 1 divided by 2 pi right parenthesis square root of left parenthesis K rightwards arrow over short leftwards arrow divided by rightwards arrow over short leftwards arrow m right parenthesis end root    
  2. left parenthesis 1 divided by 2 pi right parenthesis square root of left parenthesis 2 K rightwards arrow over short leftwards arrow divided by rightwards arrow over short leftwards arrow m right parenthesis end root    
  3. left parenthesis 1 divided by 2 pi right parenthesis square root of left parenthesis 3 K rightwards arrow over short leftwards arrow divided by rightwards arrow over short leftwards arrow m right parenthesis end root    
  4. left parenthesis 1 divided by 2 pi right parenthesis square root of left parenthesis m rightwards arrow over short leftwards arrow divided by rightwards arrow over short leftwards arrow K right parenthesis end root    

The correct answer is: left parenthesis 1 divided by 2 pi right parenthesis square root of left parenthesis 3 K rightwards arrow over short leftwards arrow divided by rightwards arrow over short leftwards arrow m right parenthesis end root


    n equals fraction numerator 1 over denominator 2 pi end fraction square root of fraction numerator K subscript e f f e c t i v e end subscript over denominator m end fraction end root equals fraction numerator 1 over denominator 2 pi end fraction square root of fraction numerator left parenthesis K plus 2 K right parenthesis over denominator m end fraction end root=fraction numerator 1 over denominator 2 pi end fraction square root of fraction numerator 3 K over denominator m end fraction end root

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