Maths-
General
Easy

Question

A group of students were allotted a quadrilateral patch in the school campus to make a garden. They cleared up the patch and decided to grow medicinal plants. Find the area of the patch, if the dimensions are as given in the figure.

hintHint:

Using pythagoras theorem, find the length of  side AC.
area of patch ABCD = area of Δ ABC + area of Δ ADC
Find area of area of Δ ADC by heron's formula for finding the area of triangle
 

The correct answer is: 306 m2


    Step1 :- Find the length of side Ac using pythagoras theorem,
    In Δ ABC , AC2 = AB2 + BC2
    We know that AB = 9 and BC = 40
    Substituting the values we get  AC2 = 92 + 402 = 81+1600 = 1681 =412
    We get AC =  41 m
    Step2:- Find the area of Δ ABC,
    Here,Δ ABC is a right angle triangle .
    Area of right angle triangle = ½ (product of lengths of  perpendicular sides)
    Area of Δ ABC = ½ (40 × 9)
    Area of Δ ABC = 180 m2
    Step 3:- Find the area of Δ ADC from heron's formula
    Here, side length of triangle are 15,28 and 41 m
    Heron's formula for area of triangle with side length
    a,b,c are Area =space square root of s left parenthesis s minus a right parenthesis left parenthesis s minus b right parenthesis left parenthesis s minus c right parenthesis end root

    Where s = fraction numerator a plus b plus c over denominator 2 end fraction
    Let a = 28 ;b = 15 ;c = 41                                               

    We get sfraction numerator 28 plus 15 plus 41 over denominator 2 end fraction = 42

    Area =  square root of 42 left parenthesis 42 minus 28 right parenthesis left parenthesis 42 minus 15 right parenthesis left parenthesis 42 minus 41 right parenthesis end root

    square root of 42 cross times 14 cross times 27 cross times I end root
    square root of 15876 equals 126 straight m squared
    We get area of Δ ADC = 126 (m2)

     
    Step 4:- Find the area of the Patch
    area of patch ABCD = area of Δ ABC + area of Δ ADC

    = 180 m2 + 126 m2

    = 306  m2
    Therefore area of patch ABCD = 306  m2.


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