Question
Find the image of △ 𝐴𝑂𝐵 after 90° anticlockwise rotation about O.
Hint:
Note that anticlockwise means rotate towards left.
The correct answer is: △ 𝐴𝑂𝐵 → △ BOC
First try to turn the given figure through given angle towards left and notice which new vertex is has taken place of the original vertex.
We will notice that when the given figure is rotated 90° anticlockwise A → B and B → C and O → O
So, △ 𝐴𝑂𝐵 → △ BOC
( keep order in which triangle is defined in mind)
Related Questions to study
II) What is the symmetric property of congruent triangles?
II) What is the symmetric property of congruent triangles?
Find the image of 𝐵𝑄 after 90° clockwise rotation about O
Find the image of 𝐵𝑄 after 90° clockwise rotation about O
If 6 • 2k = 36 , what is the value of 4 - 2k ?
Note:
Here, first we divide by 6 and then again divide by 2. We could also have multiplied 6 and 2 to get 12 and then divide the equation throughout by 12. We can divide both sides by any number except 0. A fraction with 0 as denominator is not defined.
If 6 • 2k = 36 , what is the value of 4 - 2k ?
Note:
Here, first we divide by 6 and then again divide by 2. We could also have multiplied 6 and 2 to get 12 and then divide the equation throughout by 12. We can divide both sides by any number except 0. A fraction with 0 as denominator is not defined.
I) Is every triangle congruent to itself? Explain why or why not.
I) Is every triangle congruent to itself? Explain why or why not.
A point (x, y) gets translated to the image (9,17) under translation ((𝑥, 𝑦) → (𝑥 − 2, 𝑦 − 1). Find the coordinates of the original point.
A point (x, y) gets translated to the image (9,17) under translation ((𝑥, 𝑦) → (𝑥 − 2, 𝑦 − 1). Find the coordinates of the original point.
If (-2, -9) translates to (-9, 2), then (-5, -1) translates to
If (-2, -9) translates to (-9, 2), then (-5, -1) translates to
Segments OA and OB are radii of the semicircle above. Arc AB has length 3π and OA = 5. What is the value of x ?
A semicircle is formed when a lining passing through the center touches the circle's two ends. As a result of joining two semicircles, we get a circular shape.
A circle is a collection of points equidistant from the circle's center. A radius is a common distance between the center of a circle and its point.
¶Area of a semicircle = 1/2 (π r2)
where r is the radius.
The value is 3.14 or 22/7.
¶Semi circle Formula
¶
| Area | ¶(πr2)/2 | ¶
| Perimeter (Circumference) | ¶(½)πd + d; when diameter (d) is known πr + 2r | ¶
| Angle in a semicircle | ¶¶90 degrees, i.e., right angle ¶ | ¶
| Central angle | ¶180 degrees | ¶
Segments OA and OB are radii of the semicircle above. Arc AB has length 3π and OA = 5. What is the value of x ?
A semicircle is formed when a lining passing through the center touches the circle's two ends. As a result of joining two semicircles, we get a circular shape.
A circle is a collection of points equidistant from the circle's center. A radius is a common distance between the center of a circle and its point.
¶Area of a semicircle = 1/2 (π r2)
where r is the radius.
The value is 3.14 or 22/7.
¶Semi circle Formula
¶
| Area | ¶(πr2)/2 | ¶
| Perimeter (Circumference) | ¶(½)πd + d; when diameter (d) is known πr + 2r | ¶
| Angle in a semicircle | ¶¶90 degrees, i.e., right angle ¶ | ¶
| Central angle | ¶180 degrees | ¶
𝐴𝐵 → 𝐶𝐷 is a rotation. Which of the following statements is true?
𝐴𝐵 → 𝐶𝐷 is a rotation. Which of the following statements is true?
In the figure, ABCD is a trapezium with 
. Find the area of trapezium if 
In the figure, ABCD is a trapezium with . Find the area of trapezium if
In △ ABC and △ DEF , ∠A ≅ ∠D, ∠B ≅ ∠E , then ∠C ≅ ?
In △ ABC and △ DEF , ∠A ≅ ∠D, ∠B ≅ ∠E , then ∠C ≅ ?
The table above shows two pairs of values for the linear function f. The function can be written in the form 
, where a and b are constants. What is the value of a + b ?
Note:
We can take a different approach to solving the linear equations. The above method is called method of elimination. We may also use the method of substitution; which is finding the values one variable, say a , in terms of b , from the first equation and replacing this value in the second equation to get a linear equation in one variable , b . Then solve it to find b, and use it in the previous equation to find a.
The table above shows two pairs of values for the linear function f. The function can be written in the form , where a and b are constants. What is the value of a + b ?
Note:
We can take a different approach to solving the linear equations. The above method is called method of elimination. We may also use the method of substitution; which is finding the values one variable, say a , in terms of b , from the first equation and replacing this value in the second equation to get a linear equation in one variable , b . Then solve it to find b, and use it in the previous equation to find a.
