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Maths-

General

Easy

Question

If $theta equals p over q$ and $theta equals 3 ϕ open parentheses 0 less than theta less than pi over 2 close parentheses$ ,then $fraction numerator p over denominator sin invisible function application ϕ end fraction minus fraction numerator q over denominator cos invisible function application ϕ end fraction equals$

$2 \sqrt{(p^{2} - q^{2})}$
$2 \sqrt{(p^{2} + q^{2})}$
$\sqrt{(p^{2} + q^{2})}$
$3 \sqrt{(p^{2} + q^{2})}$

The correct answer is: $2 square root of open parentheses p squared plus q squared close parentheses end root$

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