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General

General

Easy

Question

$I f space fraction numerator x cubed left parenthesis x plus 1 right parenthesis to the power of 23 left parenthesis x plus 2 right parenthesis to the power of 333 over denominator 888 left parenthesis x plus 3 right parenthesis left parenthesis x plus 33 right parenthesis squared left parenthesis x plus 333 right parenthesis to the power of 4 end fraction less than 0$

$(- 33, - 3) \cup (- 2, - 1) \cup (0, \infty)$
$(- 333, - 33) \cup (- 3, - 2) \cup (- 1, 0)$
(-2, 0)
$(- 3, - 2) \cup (- 1, 0)$

The correct answer is: $left parenthesis negative 3 comma space minus 2 right parenthesis space union space left parenthesis negative 1 comma space 0 right parenthesis$

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