Maths-
General
Easy

Question

Length of the fence of a trapezium shaped field ABCD is 120m. If BC = 48m , CD = 17m and AD = 40m , Find the area of this field. Side AB is perpendicular to the parallel sides AD and BC.

hintHint:

Find the length of AB from perimeter and other given sides of trapezium .
Now , find the area of Trapezium =  ½ height × (sum of lengths of parallel sides).

The correct answer is: 660 m2


    Ans :-660 m2.
     Explanation :-
    Step 1:- Find the length of AB from perimeter and other given side lengths.
    Perimeter of trapezium = 120 m
    Given BC = 48 m ;CD = 17 m and AD = 40 m.
    Side AB is perpendicular to the parallel sides AD and BC
    Perimeter of trapezium = AB+BC+CD+DA
    not stretchy rightwards double arrow 120 m equals A B plus 48 m plus 17 m plus 40 m
    not stretchy rightwards double arrow 120 m equals A B plus 105 m not stretchy rightwards double arrow A B equals 120 minus 105 equals 15 m

    Step 2:- find the area of trapezium
    text  Area of trapezium  end text equals 1 half left parenthesis text  height  end text right parenthesis text  (sum of lengths of parallel sides)  end text
    text  Area of trapezium  end text equals 1 half left parenthesis 15 right parenthesis left parenthesis 40 plus 48 right parenthesis equals left parenthesis 15 cross times 88 right parenthesis divided by 2 equals 15 cross times 44
    = 660 m2
    Therefore, Area of trapezium shaped field ABCD  = 660 m2.

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