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Physics-

General

Easy

Question

A parallel plate capacitor of plate separation 2 mm is connected in an electric circuit having source voltage 400V. If the plate area is 60cm² , then the value of displacement current for 10^-6sec will be

1.062 amp
$1.062 \times 10^{- 2}$ amp
$1.062 \times 10^{- 3}$ amp
$1.062 \times 10^{- 4}$ amp

The correct answer is: $1.062 cross times 10 to the power of negative 2 end exponent$ amp

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