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Question

If a subscript 1 end subscript comma a subscript 2 end subscript comma a subscript 3 end subscript comma horizontal ellipsis comma a subscript n end subscript are the n arithmetic means between a and b, then 2 not stretchy sum from i equals 1 to n of a subscript i end subscript equals

  1. a b    
  2. n left parenthesis a plus b right parenthesis    
  3. n a b    
  4. fraction numerator left parenthesis a plus b right parenthesis over denominator n end fraction    

The correct answer is: n left parenthesis a plus b right parenthesis


    Since, a subscript 1 end subscript comma a subscript 2 end subscript comma horizontal ellipsis comma a subscript n end subscript are n AM’s between a and b, then
    a subscript i end subscript equals a plus i fraction numerator left parenthesis b minus a right parenthesis over denominator n plus 1 end fraction
    therefore 2 not stretchy sum from i equals 1 to n of a subscript i end subscript equals 2 open square brackets not stretchy sum a plus fraction numerator open parentheses b minus a close parentheses over denominator n plus 1 end fraction not stretchy sum i close square brackets
    equals 2 open square brackets n a plus fraction numerator open parentheses b minus a close parentheses over denominator n plus 1 end fraction. blank n fraction numerator open parentheses n plus 1 close parentheses over denominator 2 end fraction close square brackets
    equals n left parenthesis a plus b right parenthesis

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