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    Maths-
    General
    Easy

    Question

    If A = open square brackets table row 2 0 1 row 2 1 3 row 1 cell negative 1 end cell 0 end table close square brackets then A2 – 5A + 6I =

    1. open square brackets table row 1 cell negative 1 end cell cell negative 5 end cell row cell negative 1 end cell cell negative 1 end cell 4 row cell negative 3 end cell cell negative 10 end cell 4 end table close square brackets    
    2. open square brackets table row 1 cell negative 1 end cell cell negative 3 end cell row cell negative 1 end cell cell negative 1 end cell cell negative 10 end cell row cell negative 5 end cell 4 4 end table close square brackets    
    3. 0    
    4. I    

    The correct answer is: open square brackets table row 1 cell negative 1 end cell cell negative 3 end cell row cell negative 1 end cell cell negative 1 end cell cell negative 10 end cell row cell negative 5 end cell 4 4 end table close square brackets

      To find the value of A squared minus 5 A plus 6 I.
      Given, A = open square brackets table row 2 0 1 row 2 1 3 row 1 cell negative 1 end cell 0 end table close square brackets .
      Error converting from MathML to accessible text.
      5A = Error converting from MathML to accessible text.
      6I = Error converting from MathML to accessible text.
      A squared minus 5 A plus 6 I = Error converting from MathML to accessible text. - Error converting from MathML to accessible text. + Error converting from MathML to accessible text.
      = open square brackets table row 1 cell negative 1 end cell cell negative 3 end cell row cell negative 1 end cell cell negative 1 end cell cell negative 10 end cell row cell negative 5 end cell 4 4 end table close square brackets

      Therefore, A squared minus 5 A plus 6 I  = open square brackets table row 1 cell negative 1 end cell cell negative 3 end cell row cell negative 1 end cell cell negative 1 end cell cell negative 10 end cell row cell negative 5 end cell 4 4 end table close square brackets.

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