Maths-
General
Easy

Question

If latus rectum of ellipse x2tan2theta  + y2sec2theta = 1 is fraction numerator 1 over denominator 2 end fraction then theta {0 < theta < pi/4} is equal to

  1. fraction numerator pi over denominator 36 end fraction    
  2. fraction numerator pi over denominator 12 end fraction    
  3. fraction numerator pi over denominator 10 end fraction    
  4. None of these    

hintHint:

use the definition of ellipse to find out the eccentricity and length of latus rectum. then use trigonometric functions to simplify the expression.

The correct answer is: fraction numerator pi over denominator 12 end fraction



    fraction numerator pi over denominator 12 end fraction

    Here, a= 1/tanѲ
    b= 1/secѲ
    we know that e2 = 1-b2/a2
    e2= 1-sin2Ѳ = cos2Ѳ
    we know that length of latus rectum = 2b2/a=2a(1-e2)
    2a(1-cos2Ѳ)=2asin2Ѳ=1/2
    a=1/tanѲ=cot Ѳ=  cosѲ/sinѲ
    => length of latus rectum = 2 cosѲ sin2Ѳ/sinѲ
    sin2Ѳ = ½
    => 2Ѳ = π/6, 5π/6
    Ѳ= π/12, 5π/12

    the focal chord that is perpendicular to the major axis of the ellipse is called the latus rectum of the ellipse.

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