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Question

In the figuretext ,  end text stack D E with bar on top divided by divided by stack B C with bar on top text end textand areatext end text left parenthesis triangle A D E right parenthesis equals text  area  end text left parenthesis triangle B C E D right parenthesis. text end textThe value oftext end text fraction numerator B D over denominator A B end fraction equals

  1. 1    
  2. fraction numerator 1 over denominator 3 end fraction    
  3. fraction numerator 1 over denominator 4 end fraction    
  4. fraction numerator 1 over denominator 2 end fraction    

The correct answer is: fraction numerator 1 over denominator 2 end fraction

Related Questions to study

General
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In the figure, angle A equals angle C E D, AB = 9 cm, AD = 7 cm, CD = 8 cm and CE = 10 cm Then DE = ?

if 2 angles are same in a triangle, then the triangles are similar. we can use the property that ratio of sides remains same in similar triangles.

In the figure, angle A equals angle C E D, AB = 9 cm, AD = 7 cm, CD = 8 cm and CE = 10 cm Then DE = ?

Maths-General

if 2 angles are same in a triangle, then the triangles are similar. we can use the property that ratio of sides remains same in similar triangles.

General
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In the figuretext ,  end text stack A B with bar on top divided by divided by stack Q R with bar on top text  . If  end text A B equals 3 c m comma P B equals 2 c m text  and end text PR = 6 cm then QR = ? cm

we can use the property that ratio of sides remains same in similar triangles

In the figuretext ,  end text stack A B with bar on top divided by divided by stack Q R with bar on top text  . If  end text A B equals 3 c m comma P B equals 2 c m text  and end text PR = 6 cm then QR = ? cm

Maths-General

we can use the property that ratio of sides remains same in similar triangles

General
Maths-

In the figuretext ,  end text stack A B with bar on top divided by divided by stack C D with bar on top text  and  end text stack A C with bar on top intersection stack B D with bar on top equals 0. text  If  end text O A equals 3 x minus 1 text  , end text OB = 2x + 1, OC = 5x – 3, OD = 6x – 5 then AC = ? units.

solving the quadratic equations by the factorization method is used. in this method, the linear term is broken down into 2 terms so that we can take out the common factors from the terms and convert the equation into product form.

In the figuretext ,  end text stack A B with bar on top divided by divided by stack C D with bar on top text  and  end text stack A C with bar on top intersection stack B D with bar on top equals 0. text  If  end text O A equals 3 x minus 1 text  , end text OB = 2x + 1, OC = 5x – 3, OD = 6x – 5 then AC = ? units.

Maths-General

solving the quadratic equations by the factorization method is used. in this method, the linear term is broken down into 2 terms so that we can take out the common factors from the terms and convert the equation into product form.

parallel
General
Maths-

Two line segments text end text stack A B with rightwards arrow on top text  and  end text stack C D with bar on top text end text intersect at E such that triangle A C E tilde operator triangle B D E. If AE = 4cm, BE = 3cm, CE=6cm and DE = x cm then x = ?

We can also use trigonometry to solve this question since all the angles are same in similar triangles. Angle AEC = angle BED.

Two line segments text end text stack A B with rightwards arrow on top text  and  end text stack C D with bar on top text end text intersect at E such that triangle A C E tilde operator triangle B D E. If AE = 4cm, BE = 3cm, CE=6cm and DE = x cm then x = ?

Maths-General

We can also use trigonometry to solve this question since all the angles are same in similar triangles. Angle AEC = angle BED.

General
maths-

From the adjacent figure ,the values of x and y are

From the adjacent figure ,the values of x and y are

maths-General
General
Maths-

In the given figure, ABC is an Isosceles Triangle in which AB = AC, then

we can also use trigonometry to solve this problem. For the same perpendicular distance from the vertex, the length of side increases with increase in the vertex angle since the perpendicular is the cosine component of the side.
height = side x cos(theta). we know that cosine is a decreasing function. therefore, to keep the height same, the side has to increase.

In the given figure, ABC is an Isosceles Triangle in which AB = AC, then

Maths-General

we can also use trigonometry to solve this problem. For the same perpendicular distance from the vertex, the length of side increases with increase in the vertex angle since the perpendicular is the cosine component of the side.
height = side x cos(theta). we know that cosine is a decreasing function. therefore, to keep the height same, the side has to increase.

parallel
General
maths-

In the figure, AB = BC = CD = DE = EF and AF = AE. Then angle A = ?

In the figure, AB = BC = CD = DE = EF and AF = AE. Then angle A = ?

maths-General
General
Maths-

In the figure, AB = AC, angle A = 48° and angle A C D = 18° . Then

an isosceles triangle is one that has two of its sides equal and the base angles equal to each other.

In the figure, AB = AC, angle A = 48° and angle A C D = 18° . Then

Maths-General

an isosceles triangle is one that has two of its sides equal and the base angles equal to each other.

General
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In the figure, ‘x° ’ and ‘y° ’ are two exterior angle measures of triangle A B C . Then x° + y° is

if one of the angles were acute then we'd not have been able to conclude whether the sum of the angles were greater than or less than 180 degrees.

In the figure, ‘x° ’ and ‘y° ’ are two exterior angle measures of triangle A B C . Then x° + y° is

Maths-General

if one of the angles were acute then we'd not have been able to conclude whether the sum of the angles were greater than or less than 180 degrees.

parallel
General
Maths-

The perimeter of the following figure is

perimeter is the sum of the sides of a polygon.

The perimeter of the following figure is

Maths-General

perimeter is the sum of the sides of a polygon.

General
chemistry-

Two pupils Ram and Shyam have taken lime water in a vessel, as shown in the figure. Ram is inhaling air from straw A and Shyam is blowing air through straw B. In which case lime water turns milky faster and Why?

Two pupils Ram and Shyam have taken lime water in a vessel, as shown in the figure. Ram is inhaling air from straw A and Shyam is blowing air through straw B. In which case lime water turns milky faster and Why?

chemistry-General
General
maths-

If straight A equals open square brackets a subscript i j end subscript close square brackets subscript 2 cross times 2 end subscript where a subscript i j end subscript equals i plus j then A is equal to

If straight A equals open square brackets a subscript i j end subscript close square brackets subscript 2 cross times 2 end subscript where a subscript i j end subscript equals i plus j then A is equal to

maths-General
parallel
General
Maths-

The range of the function  f left parenthesis x right parenthesis equals square root of left parenthesis x minus 1 right parenthesis left parenthesis 3 minus x right parenthesis end root text  is  end text

In this question, we have to find the range of f(x)=square root of open parentheses x minus 1 close parentheses open parentheses 3 minus x close parentheses end root. Here solve the function and find when function is at maximum and minimum.

The range of the function  f left parenthesis x right parenthesis equals square root of left parenthesis x minus 1 right parenthesis left parenthesis 3 minus x right parenthesis end root text  is  end text

Maths-General

In this question, we have to find the range of f(x)=square root of open parentheses x minus 1 close parentheses open parentheses 3 minus x close parentheses end root. Here solve the function and find when function is at maximum and minimum.

General
maths-

The range of the function  sin invisible function application open parentheses sin to the power of negative 1 end exponent invisible function application x plus cos to the power of negative 1 end exponent invisible function application x close parentheses comma vertical line x vertical line less or equal than 1 text  is  end text

The range of the function  sin invisible function application open parentheses sin to the power of negative 1 end exponent invisible function application x plus cos to the power of negative 1 end exponent invisible function application x close parentheses comma vertical line x vertical line less or equal than 1 text  is  end text

maths-General
General
maths-

The domain of the function f left parenthesis x right parenthesis equals log subscript e invisible function application left parenthesis x minus left square bracket x right square bracket right parenthesis text  is  end text

The domain of the function f left parenthesis x right parenthesis equals log subscript e invisible function application left parenthesis x minus left square bracket x right square bracket right parenthesis text  is  end text

maths-General
parallel

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