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Physics-

General

Easy

Question

A point moves along the arc of a circle of radius R. Its speed varies as $v equals a square root of s comma$ where a is constant and s is the arc length travelled by the particle. The angle $alpha$ between the vector of total acceleration and the vector of velocity is given by

$\tan^{- 1} (R /S)$
$\tan^{- 1} (R / s)$
$\tan^{- 1} (2 S / R)$
$\tan^{- 1} (S / R)$

The correct answer is: $tan to the power of negative 1 end exponent invisible function application open parentheses 2 S divided by R close parentheses$

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