Have a query? Ask a Tutor!!

Access to best educators and exclusive paper discussions

Offsite Campus Turito Championship

Can’t find what you’re looking for?

Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

Homework- One to One Solutions
Understand concepts to solve better
Get your doubts solved instantly

Physics-

General

Easy

Question

A section of fixed smooth circular track of radius R in vertical plane is shown in the figure. A block is released from position A and leaves the track at B. The radius of curvature of its trajectory when it just leaves the track at B is:

R
R/4
R/2
none of these

The correct answer is: R/2

Related Questions to study

If $f left parenthesis x comma y right parenthesis to the power of minus end exponent square root of x to the power of 2 end exponent plus y to the power of 2 end exponent end root plus square root of left parenthesis x minus 1 right parenthesis to the power of 2 end exponent plus y to the power of 2 end exponent end root plus square root of x to the power of 2 end exponent plus left parenthesis y minus 1 right parenthesis to the power of 2 end exponent end root plus square root of left parenthesis x minus 3 right parenthesis to the power of 2 end exponent plus left parenthesis y minus 4 right parenthesis to the power of 2 end exponent end root comma$ where $x comma y stack I with hat on top R comma$ then the minimum value of $f left parenthesis x comma y right parenthesis$ is

If $f left parenthesis x comma y right parenthesis to the power of minus end exponent square root of x to the power of 2 end exponent plus y to the power of 2 end exponent end root plus square root of left parenthesis x minus 1 right parenthesis to the power of 2 end exponent plus y to the power of 2 end exponent end root plus square root of x to the power of 2 end exponent plus left parenthesis y minus 1 right parenthesis to the power of 2 end exponent end root plus square root of left parenthesis x minus 3 right parenthesis to the power of 2 end exponent plus left parenthesis y minus 4 right parenthesis to the power of 2 end exponent end root comma$ where $x comma y stack I with hat on top R comma$ then the minimum value of $f left parenthesis x comma y right parenthesis$ is

Let $f left parenthesis x right parenthesis equals l n invisible function application open parentheses fraction numerator 1 minus x over denominator 1 plus x end fraction close parentheses$ the set of values of ‘ a ’ for which $f left parenthesis alpha right parenthesis plus f open parentheses alpha to the power of 2 end exponent close parentheses equals f open parentheses fraction numerator alpha over denominator alpha to the power of 2 end exponent minus alpha plus 1 end fraction close parentheses$ is satisfied are

Let $f left parenthesis x right parenthesis equals l n invisible function application open parentheses fraction numerator 1 minus x over denominator 1 plus x end fraction close parentheses$ the set of values of ‘ a ’ for which $f left parenthesis alpha right parenthesis plus f open parentheses alpha to the power of 2 end exponent close parentheses equals f open parentheses fraction numerator alpha over denominator alpha to the power of 2 end exponent minus alpha plus 1 end fraction close parentheses$ is satisfied are

If $f open parentheses x plus y close parentheses equals f open parentheses x. y close parentheses for all x comma y element of R text end text$ and f(2011)=2010 $text end text$ then f(2012)=

If $f open parentheses x plus y close parentheses equals f open parentheses x. y close parentheses for all x comma y element of R text end text$ and f(2011)=2010 $text end text$ then f(2012)=

parallel

If $2 f left parenthesis x right parenthesis plus x f open parentheses fraction numerator 1 over denominator x end fraction close parentheses minus 2 f open parentheses open vertical bar square root of 2 sin invisible function application pi open parentheses x plus fraction numerator 1 over denominator 4 end fraction close parentheses close vertical bar close parentheses equals 4 c o s to the power of 2 end exponent invisible function application open parentheses fraction numerator pi x over denominator 2 end fraction close parentheses plus x c o s invisible function application fraction numerator pi over denominator x end fraction comma for all x element of R minus left curly bracket 0 right curly bracket$ then which of the following statement(s) is/are true?

If $2 f left parenthesis x right parenthesis plus x f open parentheses fraction numerator 1 over denominator x end fraction close parentheses minus 2 f open parentheses open vertical bar square root of 2 sin invisible function application pi open parentheses x plus fraction numerator 1 over denominator 4 end fraction close parentheses close vertical bar close parentheses equals 4 c o s to the power of 2 end exponent invisible function application open parentheses fraction numerator pi x over denominator 2 end fraction close parentheses plus x c o s invisible function application fraction numerator pi over denominator x end fraction comma for all x element of R minus left curly bracket 0 right curly bracket$ then which of the following statement(s) is/are true?

Period of $f left parenthesis x right parenthesis equals s i n invisible function application fraction numerator pi x over denominator left parenthesis n minus 1 right parenthesis factorial end fraction plus c o s invisible function application fraction numerator pi x over denominator n factorial end fraction$ Is

Period of $f left parenthesis x right parenthesis equals s i n invisible function application fraction numerator pi x over denominator left parenthesis n minus 1 right parenthesis factorial end fraction plus c o s invisible function application fraction numerator pi x over denominator n factorial end fraction$ Is

Consider the function $f left parenthesis x right parenthesis equals s g n invisible function application left parenthesis x right parenthesis text and end text g left parenthesis x right parenthesis equals x open parentheses 1 minus x to the power of 2 end exponent close parentheses$ then which of the following does not hold good?

Consider the function $f left parenthesis x right parenthesis equals s g n invisible function application left parenthesis x right parenthesis text and end text g left parenthesis x right parenthesis equals x open parentheses 1 minus x to the power of 2 end exponent close parentheses$ then which of the following does not hold good?

parallel

The domain of the function $square root of 1 minus f left parenthesis x right parenthesis end root text where end text f to the power of 3 end exponent left parenthesis x right parenthesis equals 1 minus x to the power of 3 end exponent minus 3 x f left parenthesis x right parenthesis. x element of R text is end text left parenthesis f left parenthesis 1 right parenthesis not equal to negative 1 right parenthesis$

The domain of the function $square root of 1 minus f left parenthesis x right parenthesis end root text where end text f to the power of 3 end exponent left parenthesis x right parenthesis equals 1 minus x to the power of 3 end exponent minus 3 x f left parenthesis x right parenthesis. x element of R text is end text left parenthesis f left parenthesis 1 right parenthesis not equal to negative 1 right parenthesis$

If $f left parenthesis x right parenthesis equals s i n to the power of negative 1 end exponent invisible function application x text and end text g left parenthesis x right parenthesis equals left square bracket s i n invisible function application x left parenthesis c o s invisible function application x right parenthesis right square bracket plus left square bracket c o s invisible function application left parenthesis s i n invisible function application x right parenthesis right square bracket comma text end text$ then range of f(g(x)) is

If $f left parenthesis x right parenthesis equals s i n to the power of negative 1 end exponent invisible function application x text and end text g left parenthesis x right parenthesis equals left square bracket s i n invisible function application x left parenthesis c o s invisible function application x right parenthesis right square bracket plus left square bracket c o s invisible function application left parenthesis s i n invisible function application x right parenthesis right square bracket comma text end text$ then range of f(g(x)) is

Domain of the function $f left parenthesis x right parenthesis equals fraction numerator 1 over denominator square root of l n invisible function application c o t to the power of negative 1 end exponent invisible function application x end root end fraction$ is

Domain of the function $f left parenthesis x right parenthesis equals fraction numerator 1 over denominator square root of l n invisible function application c o t to the power of negative 1 end exponent invisible function application x end root end fraction$ is

parallel

If $f colon left parenthesis 0 comma pi right parenthesis rightwards arrow R$ defined by $f open parentheses x close parentheses equals stretchy sum from k equals 1 to n of open square brackets 1 plus sin invisible function application k x close square brackets comma$ where [x] denotes the integral part of x, then range of f(x) is

If $f colon left parenthesis 0 comma pi right parenthesis rightwards arrow R$ defined by $f open parentheses x close parentheses equals stretchy sum from k equals 1 to n of open square brackets 1 plus sin invisible function application k x close square brackets comma$ where [x] denotes the integral part of x, then range of f(x) is

If [x] denotes the integral part of x, then domain of the function $f left parenthesis x right parenthesis equals fraction numerator square root of 3 minus x end root over denominator left parenthesis x minus 1 right parenthesis left parenthesis x minus 2 right parenthesis left parenthesis x minus 3 right parenthesis end fraction plus s i n to the power of negative 1 end exponent invisible function application open square brackets fraction numerator 3 x minus 2 over denominator 2 end fraction close square brackets$ is

If [x] denotes the integral part of x, then domain of the function $f left parenthesis x right parenthesis equals fraction numerator square root of 3 minus x end root over denominator left parenthesis x minus 1 right parenthesis left parenthesis x minus 2 right parenthesis left parenthesis x minus 3 right parenthesis end fraction plus s i n to the power of negative 1 end exponent invisible function application open square brackets fraction numerator 3 x minus 2 over denominator 2 end fraction close square brackets$ is

The domain of the function $f left parenthesis x right parenthesis equals fraction numerator 1 over denominator square root of vertical line t a n invisible function application x vertical line minus t a n invisible function application x end root end fraction$ is

The domain of the function $f left parenthesis x right parenthesis equals fraction numerator 1 over denominator square root of vertical line t a n invisible function application x vertical line minus t a n invisible function application x end root end fraction$ is

parallel

The domain of definition of the function $Error converting from MathML to accessible text.$

The domain of definition of the function $Error converting from MathML to accessible text.$

Let $f colon left square bracket negative 1 , 1 right square bracket rightwards arrow R$ be a function defined as $y equals f left parenthesis x right parenthesis text and end text g left parenthesis x right parenthesis equals l o g subscript 2 e end subscript invisible function application left square bracket x right square bracket$ ; ([.] denotes greatest integer function) then number of integers in the domain of f (g(x)) is/are

Let $f colon left square bracket negative 1 , 1 right square bracket rightwards arrow R$ be a function defined as $y equals f left parenthesis x right parenthesis text and end text g left parenthesis x right parenthesis equals l o g subscript 2 e end subscript invisible function application left square bracket x right square bracket$ ; ([.] denotes greatest integer function) then number of integers in the domain of f (g(x)) is/are

Statement - I : Let f(x) be a function such that $f left parenthesis x minus 1 right parenthesis plus f left parenthesis x plus 1 right parenthesis equals square root of 2 f left parenthesis x right parenthesis$ for all x $element of$ R then f is periodic
Statement - II : There exists a function with period 8

Statement - I : Let f(x) be a function such that $f left parenthesis x minus 1 right parenthesis plus f left parenthesis x plus 1 right parenthesis equals square root of 2 f left parenthesis x right parenthesis$ for all x $element of$ R then f is periodic
Statement - II : There exists a function with period 8

parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.