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If net force on a system in a particular direction is zero (say in horizontal direction) we can apply: Here R stands for the masses which are moving towards right and L for the masses towards left, x is displacement, v is velocity and a the acceleration (all with respect to ground). A small block of mass m = 1 kg is placed over a wedge of mass M = 4 kg as shown in figure. Mass m is released from rest. All surfaces are smooth. Origin O is as shown. At the same instant reaction on the wedge from the ground is N
- 42.5
- 40
- 43.46
- None of these
The correct answer is: 42.5
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If net force on a system in a particular direction is zero (say in horizontal direction) we can apply: Here R stands for the masses which are moving towards right and L for the masses towards left, x is displacement, v is velocity and a the acceleration (all with respect to ground). A small block of mass m = 1 kg is placed over a wedge of mass M = 4 kg as shown in figure. Mass m is released from rest. All surfaces are smooth. Origin O is as shown. Normal reaction between the two blocks at an instant when absolute acceleration of m is m/s2 at 60° with horizontal is N. Normal reaction at this instant is making with horizontal:
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