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Question

The adjacent graph shows the extension (l) of a wire of length 1m suspended from the top of a roof at one end and with a load W connected to the other end. If the cross-sectional area of the wire is 10 to the power of negative 6 blank end exponent m to the power of 2 blank end exponent, calculate the Young’s modulus of the material of the wire.

  1. 2 cross times 10 to the power of 11 blank end exponent N m to the power of negative 2 end exponent    
  2. 2 cross times 10 to the power of negative 11 blank end exponent N m to the power of negative 2 end exponent    
  3. 3 cross times 10 to the power of 12 blank end exponent N m to the power of negative 2 end exponent    
  4. 2 cross times 10 to the power of 13 blank end exponent N m to the power of negative 2 end exponent    

The correct answer is: 2 cross times 10 to the power of 11 blank end exponent N m to the power of negative 2 end exponent


    Extensions increment l equals open parentheses fraction numerator L over denominator Y A end fraction close parentheses bullet W
    i e commagraph is a straight line passing through origin (as shown in question also), the slope of which isfraction numerator L over denominator Y A end fraction
    Slopeequals open parentheses fraction numerator L over denominator Y A end fraction close parentheses
    Y =open parentheses fraction numerator L over denominator A end fraction close parentheses open parentheses fraction numerator 1 over denominator s l o p e end fraction close parentheses
    equals open parentheses fraction numerator 1.0 over denominator 10 to the power of negative 6 end exponent end fraction close parentheses fraction numerator open parentheses 80 minus 20 close parentheses over denominator open parentheses 4 minus 1 close parentheses cross times 10 to the power of negative 4 end exponent end fraction
    equals 2.0 cross times 10 to the power of 11 end exponent N m to the power of negative 2 end exponent

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