Chemistry-
General
Easy

Question

The conductivity of 0.001 M acetic acid is 5 × 10–5 S cm–1 and logical and to the power of 0 is 390.5 S cm2 mol–1 then the calculated value of dissociation constant of acetic acid would be

  1. 81.78 × 10–4    
  2. 81.78 × 10–5    
  3. 18.78 × 10–6    
  4. 18.78 × 10–5    

The correct answer is: 18.78 × 10–6

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