Physics-
General
Easy
Question
The capacitor of capacitance C can be charged (with the help of a resistance R) by a voltage source V, by closing switch while keeping switch open. The capacitor can be connected in series with an inductor ‘L’ by closing switch and opening .
Initially, the capacitor was uncharged. Now, switch is closed and is kept open. If time constant of this circuit is , then
- after time interval , charge on the capacitor is CV/2
- after time interval 2, charge on the capacitor is CV(1 – )
- the work done by the voltage source will be half of the heat dissipated when the capacitor is fully charged
- after time interval 2, charge on the capacitor is CV(1 – )
The correct answer is: after time interval 2, charge on the capacitor is CV(1 – )
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