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Easy

Question

Two masses of 10kg and 20kg are connected by mass less spring as shown A force of 200N acts on the 20kg mass At a certain instant the acceleration of 10kg mass is 12 m divided by s to the power of 2 end exponent The acceleration of the 20kg mass at that instant is.

  1. 12 m divided by s to the power of 2 end exponent    
  2. 10 m divided by s to the power of 2 end exponent    
  3. 4 m divided by s to the power of 2 end exponent    
  4. 8 m divided by s to the power of 2 end exponent    

The correct answer is: 4 m divided by s to the power of 2 end exponent



    200 minus T equals 20 cross times a
    T equals 10 cross times a equals 10 cross times 12 equals 120 N
    200 minus 120 equals 20 cross times a
    rightwards double arrow 20 a equals 80
    rightwards double arrow a equals 4 m divided by s to the power of 2 end exponent

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