Physics-
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Question

Two insulated light rods of length l and 2l are placed in xy plane such their mid point is origin and they are free to rotate in xy plane about z-axis. Two +q charges are fixed at two ends of bigger rod and two - q charges are fixed at two ends of smaller rod.

Electric field at point (a,0,0) is E. Now if a>>l then

  1. E alpha fraction numerator 1 over denominator a to the power of 2 end exponent end fraction    
  2. E alpha fraction numerator 1 over denominator a to the power of 3 end exponent end fraction    
  3. E alpha fraction numerator 1 over denominator a to the power of 4 end exponent end fraction    
  4. E alpha fraction numerator 1 over denominator a to the power of 5 end exponent end fraction    

The correct answer is: E alpha fraction numerator 1 over denominator a to the power of 2 end exponent end fraction

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General
physics-

Two insulated light rods of length l and 2l are placed in xy plane such their mid point is origin and they are free to rotate in xy plane about z-axis. Two +q charges are fixed at two ends of bigger rod and two - q charges are fixed at two ends of smaller rod.

What is electric dipole moment of system ?

Two insulated light rods of length l and 2l are placed in xy plane such their mid point is origin and they are free to rotate in xy plane about z-axis. Two +q charges are fixed at two ends of bigger rod and two - q charges are fixed at two ends of smaller rod.

What is electric dipole moment of system ?

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Three points charges are placed at the corners of an equilateral triangle of side L as shown in the figure.

Three points charges are placed at the corners of an equilateral triangle of side L as shown in the figure.

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In the circuit shown in figure : R subscript 1 end subscript equals 10 capital omega comma L equals fraction numerator square root of 3 over denominator 10 end fraction H comma R subscript 2 end subscript equals 20 capital omega and C equals fraction numerator square root of 3 over denominator 2 end fraction mF. Current in L minus R subscript 1 end subscript circuit is I subscript 1 end subscript in C minus R subscript 2 end subscript circuit is I subscript 2 end subscript and the main current is I Phase different between I subscript 1 end subscript and I subscript 2 end subscript is

In the circuit shown in figure : R subscript 1 end subscript equals 10 capital omega comma L equals fraction numerator square root of 3 over denominator 10 end fraction H comma R subscript 2 end subscript equals 20 capital omega and C equals fraction numerator square root of 3 over denominator 2 end fraction mF. Current in L minus R subscript 1 end subscript circuit is I subscript 1 end subscript in C minus R subscript 2 end subscript circuit is I subscript 2 end subscript and the main current is I Phase different between I subscript 1 end subscript and I subscript 2 end subscript is

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In the LCR circuit shown in figure

A) current will lead the voltage
B) rms value of current is 20 A
C) power factor of the circuit is fraction numerator 1 over denominator square root of 2 end fraction
D) voltage drop across resistance is 100 V

In the LCR circuit shown in figure

A) current will lead the voltage
B) rms value of current is 20 A
C) power factor of the circuit is fraction numerator 1 over denominator square root of 2 end fraction
D) voltage drop across resistance is 100 V

physics-General
General
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In the circuit shown in fig. If both the lamps L subscript 1 end subscript and L subscript 2 end subscript are identical.

In the circuit shown in fig. If both the lamps L subscript 1 end subscript and L subscript 2 end subscript are identical.

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The vector diagram of current and voltage for a circuit is as shown. The components of the circuit will be

The vector diagram of current and voltage for a circuit is as shown. The components of the circuit will be

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The diagram shows a capacitor C and a resistor R connected in series to an ac source. V subscript 1 end subscript and V subscript 2 end subscript are voltameters and A is an ammeter consider now the following statements
I) Readings in A and V subscript 2 end subscript are always in phase
II) Reading in V subscript 1 end subscript is ahead in phase with reading in V subscript 2 end subscript
III) Readings in A and V subscript 1 end subscript are always in phase which of these statements are/is correct

The diagram shows a capacitor C and a resistor R connected in series to an ac source. V subscript 1 end subscript and V subscript 2 end subscript are voltameters and A is an ammeter consider now the following statements
I) Readings in A and V subscript 2 end subscript are always in phase
II) Reading in V subscript 1 end subscript is ahead in phase with reading in V subscript 2 end subscript
III) Readings in A and V subscript 1 end subscript are always in phase which of these statements are/is correct

physics-General
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In the circuit shown in the figure, the ac source gives a voltage V=20cos(2000t). Neglecting source resistance, the voltmeter and ammeter reading will be

In the circuit shown in the figure, the ac source gives a voltage V=20cos(2000t). Neglecting source resistance, the voltmeter and ammeter reading will be

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The resonance point in X subscript L end subscript minus f and X subscript C end subscript minus f curves is

The resonance point in X subscript L end subscript minus f and X subscript C end subscript minus f curves is

physics-General
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A constant voltage at different frequencies is applied across a capacitance C as shown in the figure. Which of the following graphs

Correctly depicts the variation of current with frequency ?

A constant voltage at different frequencies is applied across a capacitance C as shown in the figure. Which of the following graphs

Correctly depicts the variation of current with frequency ?

physics-General
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A box P and a coil Q are connected in series with an ac source of variable frequency. The rms value of emf of source is constant at 10 V. Box P contains a capacitance of 1 mu F in series with a resistance of 32 capital omega. Coil Q has a self-inductance 4.9 m H and a resistance of 68 capital omega in series. The frequency is adjusted so that the maximum current flows in P and Q.

voltage across Q is.

A box P and a coil Q are connected in series with an ac source of variable frequency. The rms value of emf of source is constant at 10 V. Box P contains a capacitance of 1 mu F in series with a resistance of 32 capital omega. Coil Q has a self-inductance 4.9 m H and a resistance of 68 capital omega in series. The frequency is adjusted so that the maximum current flows in P and Q.

voltage across Q is.

physics-General
General
physics-

A box P and a coil Q are connected in series with an ac source of variable frequency. The rms value of emf of source is constant at 10 V. Box P contains a capacitance of 1 mu F in series with a resistance of 32 capital omega. Coil Q has a self-inductance 4.9 m H and a resistance of 68 capital omega in series. The frequency is adjusted so that the maximum current flows in P and Q.

Maximum current through circuit is.

A box P and a coil Q are connected in series with an ac source of variable frequency. The rms value of emf of source is constant at 10 V. Box P contains a capacitance of 1 mu F in series with a resistance of 32 capital omega. Coil Q has a self-inductance 4.9 m H and a resistance of 68 capital omega in series. The frequency is adjusted so that the maximum current flows in P and Q.

Maximum current through circuit is.

physics-General
parallel
General
physics-

A box P and a coil Q are connected in series with an ac source of variable frequency. The rms value of emf of source is constant at 10 V. Box P contains a capacitance of 1 mu F in series with a resistance of 32 capital omega. Coil Q has a self-inductance 4.9 m H and a resistance of 68 capital omega in series. The frequency is adjusted so that the maximum current flows in P and Q.

Impedance of p at this frequency is.

A box P and a coil Q are connected in series with an ac source of variable frequency. The rms value of emf of source is constant at 10 V. Box P contains a capacitance of 1 mu F in series with a resistance of 32 capital omega. Coil Q has a self-inductance 4.9 m H and a resistance of 68 capital omega in series. The frequency is adjusted so that the maximum current flows in P and Q.

Impedance of p at this frequency is.

physics-General
General
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We know that the amplitude of oscillating system becomes maximum, when the applied frequency is equal to the intrinsic frequency of system. And this concept can be applied even in electrical a.c circuits containing L comma C and R. It is being such that when the frequency of broad casting station becomes equal to frequency of radio circuit, then the impedance (equivalent resistance) of circuit becomes minimum and maximum current flows in the circuit with the result the radio station is tuned its impedance is given by
Z equals square root of R to the power of 2 end exponent plus open parentheses W L minus fraction numerator 1 over denominator W C end fraction close parentheses to the power of 2 end exponent end root and I subscript 0 end subscript equals fraction numerator V subscript 0 end subscript over denominator Z end fraction

Now in the given circuit as shown, at a certain moment of the values of voltages and current are given When power loss through resistor is 50 watt, then angular frequency of applied a.c voltage is

We know that the amplitude of oscillating system becomes maximum, when the applied frequency is equal to the intrinsic frequency of system. And this concept can be applied even in electrical a.c circuits containing L comma C and R. It is being such that when the frequency of broad casting station becomes equal to frequency of radio circuit, then the impedance (equivalent resistance) of circuit becomes minimum and maximum current flows in the circuit with the result the radio station is tuned its impedance is given by
Z equals square root of R to the power of 2 end exponent plus open parentheses W L minus fraction numerator 1 over denominator W C end fraction close parentheses to the power of 2 end exponent end root and I subscript 0 end subscript equals fraction numerator V subscript 0 end subscript over denominator Z end fraction

Now in the given circuit as shown, at a certain moment of the values of voltages and current are given When power loss through resistor is 50 watt, then angular frequency of applied a.c voltage is

physics-General
General
physics-

We know that the amplitude of oscillating system becomes maximum, when the applied frequency is equal to the intrinsic frequency of system. And this concept can be applied even in electrical a.c circuits containing L comma C and R. It is being such that when the frequency of broad casting station becomes equal to frequency of radio circuit, then the impedance (equivalent resistance) of circuit becomes minimum and maximum current flows in the circuit with the result the radio station is tuned its impedance is given by
Z equals square root of R to the power of 2 end exponent plus open parentheses W L minus fraction numerator 1 over denominator W C end fraction close parentheses to the power of 2 end exponent end root and I subscript 0 end subscript equals fraction numerator V subscript 0 end subscript over denominator Z end fraction

Now in the given circuit as shown, at a certain moment of the values of voltages and current are given The current in the circuit is

We know that the amplitude of oscillating system becomes maximum, when the applied frequency is equal to the intrinsic frequency of system. And this concept can be applied even in electrical a.c circuits containing L comma C and R. It is being such that when the frequency of broad casting station becomes equal to frequency of radio circuit, then the impedance (equivalent resistance) of circuit becomes minimum and maximum current flows in the circuit with the result the radio station is tuned its impedance is given by
Z equals square root of R to the power of 2 end exponent plus open parentheses W L minus fraction numerator 1 over denominator W C end fraction close parentheses to the power of 2 end exponent end root and I subscript 0 end subscript equals fraction numerator V subscript 0 end subscript over denominator Z end fraction

Now in the given circuit as shown, at a certain moment of the values of voltages and current are given The current in the circuit is

physics-General
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