Two long straight conductors with currents $I subscript 1 end subscript$ and $I subscript 2 end subscript$ are along X and Y axes. The equation of locus of points of zero magnetic induction is

In the given figure the magnetic induction at the point O is

A current IA is flowing in the sides of equilateral triangle of side $4.5 cross times 10 to the power of negative 2 end exponent$ m The magnetic induction at centroid of the triangle is

The magnetic field at the centre of circular loop in the circuit shown below is

Is this quadrilateral a trapezoid?

GeneralGeneral

A thin 50 cm long metal bar with mass 750 g rests on, but is not attached to two metallic supports in a uniform 0.45T magnetic field as shown in Fig .A battery and a 25 $capital omega blank$ resistor in series are connceted to the supports. The largest voltage the battery can have without breaking the circuit at the supports (units are in ”V”) is

Solve the quadratic equation below using the Quadratic Formula $x^{2} + 5 x - 14 = 0$

GeneralGeneral

In the figure, $C A B equals 90 to the power of ring operator end exponent text and end text A D perpendicular B C.$ If AC = 75 cm AB = 100 cm and BD = 1.25 cm then AD =

we can use the property that ratio of sides remains same in similar triangles.

In the figure, $C A B equals 90 to the power of ring operator end exponent text and end text A D perpendicular B C.$ If AC = 75 cm AB = 100 cm and BD = 1.25 cm then AD =

we can use the property that ratio of sides remains same in similar triangles.

$text In the figure end text fraction numerator A O over denominator O C end fraction equals fraction numerator B O over denominator O D end fraction equals fraction numerator 1 over denominator 2 end fraction text and end text A B equals 5 c m. text The value of end text D C text is end text$

we can use the property that ratio of sides remains same in similar triangles.

$text In the figure end text fraction numerator A O over denominator O C end fraction equals fraction numerator B O over denominator O D end fraction equals fraction numerator 1 over denominator 2 end fraction text and end text A B equals 5 c m. text The value of end text D C text is end text$

we can use the property that ratio of sides remains same in similar triangles.

maths-

In the figure $text , end text stack D E with bar on top divided by divided by stack B C with bar on top text end text$ and area $text end text left parenthesis triangle A D E right parenthesis equals text area end text left parenthesis triangle B C E D right parenthesis. text end text$ The value of $text end text fraction numerator B D over denominator A B end fraction equals$

maths-General

In the figure, $angle A equals angle C E D$ , AB = 9 cm, AD = 7 cm, CD = 8 cm and CE = 10 cm Then DE = ?

if 2 angles are same in a triangle, then the triangles are similar. we can use the property that ratio of sides remains same in similar triangles.

In the figure, $angle A equals angle C E D$ , AB = 9 cm, AD = 7 cm, CD = 8 cm and CE = 10 cm Then DE = ?

if 2 angles are same in a triangle, then the triangles are similar. we can use the property that ratio of sides remains same in similar triangles.

In the figure $text , end text stack A B with bar on top divided by divided by stack Q R with bar on top text . If end text A B equals 3 c m comma P B equals 2 c m text and end text$ PR = 6 cm then QR = ? cm

we can use the property that ratio of sides remains same in similar triangles

In the figure $text , end text stack A B with bar on top divided by divided by stack Q R with bar on top text . If end text A B equals 3 c m comma P B equals 2 c m text and end text$ PR = 6 cm then QR = ? cm