Question
The radius of a circle is 7 meters. What is area of the circle?
The correct answer is:
Related Questions to study
Multiply: 9 × 4 =
Multiply: 9 × 4 =
Solve the quadratic equation below using the Quadratic Formula
Solve the quadratic equation below using the Quadratic Formula
In the figure, 
If AC = 75 cm AB = 100 cm and BD = 1.25 cm then AD = 
we can use the property that ratio of sides remains same in similar triangles.
In the figure, If AC = 75 cm AB = 100 cm and BD = 1.25 cm then AD =
we can use the property that ratio of sides remains same in similar triangles.
we can use the property that ratio of sides remains same in similar triangles.
we can use the property that ratio of sides remains same in similar triangles.
In the figure
and area
The value of
In the figureand areaThe value of
In the figure, 
, AB = 9 cm, AD = 7 cm, CD = 8 cm and CE = 10 cm Then DE = ?
if 2 angles are same in a triangle, then the triangles are similar. we can use the property that ratio of sides remains same in similar triangles.
In the figure, , AB = 9 cm, AD = 7 cm, CD = 8 cm and CE = 10 cm Then DE = ?
if 2 angles are same in a triangle, then the triangles are similar. we can use the property that ratio of sides remains same in similar triangles.
In the figure
PR = 6 cm then QR = ? cm
we can use the property that ratio of sides remains same in similar triangles
In the figure PR = 6 cm then QR = ? cm
we can use the property that ratio of sides remains same in similar triangles
In the figure
OB = 2x + 1, OC = 5x – 3, OD = 6x – 5 then AC = ? units.
solving the quadratic equations by the factorization method is used. in this method, the linear term is broken down into 2 terms so that we can take out the common factors from the terms and convert the equation into product form.
In the figure OB = 2x + 1, OC = 5x – 3, OD = 6x – 5 then AC = ? units.
solving the quadratic equations by the factorization method is used. in this method, the linear term is broken down into 2 terms so that we can take out the common factors from the terms and convert the equation into product form.
Two line segments 
intersect at E such that 
If AE = 4cm, BE = 3cm, CE=6cm and DE = x cm then x = ?
We can also use trigonometry to solve this question since all the angles are same in similar triangles. Angle AEC = angle BED.
Two line segments intersect at E such that If AE = 4cm, BE = 3cm, CE=6cm and DE = x cm then x = ?
We can also use trigonometry to solve this question since all the angles are same in similar triangles. Angle AEC = angle BED.
From the adjacent figure ,the values of x and y are
From the adjacent figure ,the values of x and y are
In the given figure, ABC is an Isosceles Triangle in which AB = AC, then
we can also use trigonometry to solve this problem. For the same perpendicular distance from the vertex, the length of side increases with increase in the vertex angle since the perpendicular is the cosine component of the side.
height = side x cos(theta). we know that cosine is a decreasing function. therefore, to keep the height same, the side has to increase.
In the given figure, ABC is an Isosceles Triangle in which AB = AC, then
we can also use trigonometry to solve this problem. For the same perpendicular distance from the vertex, the length of side increases with increase in the vertex angle since the perpendicular is the cosine component of the side.
height = side x cos(theta). we know that cosine is a decreasing function. therefore, to keep the height same, the side has to increase.
In the figure, AB = BC = CD = DE = EF and AF = AE. Then 
= ?
In the figure, AB = BC = CD = DE = EF and AF = AE. Then = ?
In the figure, AB = AC, = 48° and 
= 18° . Then
an isosceles triangle is one that has two of its sides equal and the base angles equal to each other.
In the figure, AB = AC, = 48° and = 18° . Then
an isosceles triangle is one that has two of its sides equal and the base angles equal to each other.
In the figure, ‘x° ’ and ‘y° ’ are two exterior angle measures of 
. Then x° + y° is
if one of the angles were acute then we'd not have been able to conclude whether the sum of the angles were greater than or less than 180 degrees.
In the figure, ‘x° ’ and ‘y° ’ are two exterior angle measures of . Then x° + y° is
if one of the angles were acute then we'd not have been able to conclude whether the sum of the angles were greater than or less than 180 degrees.
The perimeter of the following figure is
perimeter is the sum of the sides of a polygon.
The perimeter of the following figure is
perimeter is the sum of the sides of a polygon.
