Maths-
General
Easy
Question
Solve each equation . is the equation an identity ? Explain .
t-27 = - (27-t)
Hint:
An equation is said to be an identity if an only if, for all values of x (or any other variable in the equation), the equation will be true. i.e. for all values of x (or any other variable in the equation), LHS = RHS.
The correct answer is: The given equation is an identity and hence, it has infinitely many solutions. i.e. for any value of t, the equation will be satisfied i.e. LHS will be equal to RHS.
Step-by-step solution:-
LHS = t - 27 ............................................... (Equation i)
RHS = - (27 - t)
∴ RHS = -(27) - (-t) ….................................... [Distributive property- a (m + n) = am + an]
∴ RHS = -27 + t
∴ RHS = t - 27 .............................................. (Equation ii)
From Equation i & ii, we get-
LHS = RHS
Hence, the given equation is not an identity.
Final Answer:-
∴ The given equation is an identity and hence, it has infinitely many solutions. i.e. for any value of t, the equation will be satisfied i.e. LHS will be equal to RHS.
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