Question
The parallel sides of a trapezium are 30cm and 10cm and the other two sides are 13cm, 21cm .find its area?
Hint:
Draw the parallel line from B parallel to AD which cuts the CD at E .
We get a triangle and parallelogram.we find the area of triangle in both heron's method and
using formula area = ½ b × h and equating we get height h
Now , find the area of Trapezium = ½ height × (sum of lengths of parallel sides).
The correct answer is: 252 cm2
Ans :- 252 cm2.
Explanation :-
Step 1:- Given lengths of parallel sides
is 10 and 30 cm .Length of non parallel
sides is 21 and 13 cm We get a triangle and parallelogram ABED
we get BE = 21 cm ; DE = 10 cm (opposites sides of parallelogram )
CE = CD-DE = 30 - 10 = 20 cm .
Explanation :-
Step 1:- Given lengths of parallel sides
is 10 and 30 cm .Length of non parallel
sides is 21 and 13 cm We get a triangle and parallelogram ABED
we get BE = 21 cm ; DE = 10 cm (opposites sides of parallelogram )
CE = CD-DE = 30 - 10 = 20 cm .
Step 2:- Equate the areas and find value of height h
Step 3:-Find the area of trapezium
Therefore, Area of trapezium ABCD = 252 cm2.
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