Question
Two poles of height 6 m and 11 m stand vertically upright on a plane ground. If the distance between their feet is 12 m, then find the distance between their tops.
Hint:
Pythagoras' theorem states that “In a right-angled triangle, the square of the hypotenuse side is equal to the sum of squares of the other two sides“. The sides of this triangle have been named Perpendicular, Base and Hypotenuse. Here, the hypotenuse is the longest side, as it is opposite to the angle 90°.
If a is the perpendicular, b is the base, and c is the hypotenuse, then according to the definition, the Pythagoras Theorem formula is given as
c2= a2 + b2
The correct answer is: Hence, the distance between the top of the poles is 13 m.
Two poles are given AB = 11 m and CD = 6m
Distance between both poles BD = 12 m
First, create a line segment CE parallel to line BD
So, BE = CD = 6 m and EC = BC = 12 m
Now, AE = AB − BE =11 − 6 = 5 m
In right angled △AEC,
(AC)2 = (AE)2 + (EC)2
(AC)2 = (5)2 + (12)2
(AC)2 = 25 + 144
(AC)2 = 169
AC = 13 m
Final Answer:
Hence, the distance between the top of the poles is 13 m.
Final Answer:
Hence, the distance between the top of the poles is 13 m.
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