Chemistry-
General
Easy

Question

  1. Can be oxidized by Tollen’s Reagent    
  2. Cannot be oxidized by Tollen’s Reagent    
  3. Can only be oxidized by CrO3    
  4. None    

The correct answer is: Can be oxidized by Tollen’s Reagent

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The ionization constant of in water is 5.6 ×´ 10-10 at 25oC. The rate constant for the reaction of and OH- to form NH3 and H2O at 25oC is 3.4 × 1010 L mol-1 s-1. The rate constant for proton transfer from water to NH3 is

The ionization constant of in water is 5.6 ×´ 10-10 at 25oC. The rate constant for the reaction of and OH- to form NH3 and H2O at 25oC is 3.4 × 1010 L mol-1 s-1. The rate constant for proton transfer from water to NH3 is

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For the curve y2 = (x + a)3 the square of the sub tangent varies as

For such questions, we should know the concept of subnormal and subtangent.

For the curve y2 = (x + a)3 the square of the sub tangent varies as

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For such questions, we should know the concept of subnormal and subtangent.

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The length of the subtangent at any point on y = f(x) is 3/8 and the length of the subnormal is 24 then the ordinate of the point is

For such questions, we should know the formula to find subtangent and subnormal.

The length of the subtangent at any point on y = f(x) is 3/8 and the length of the subnormal is 24 then the ordinate of the point is

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For such questions, we should know the formula to find subtangent and subnormal.

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The length of the portion of the tangent at any point on the curve x2/3 + y2/3 = a2/3 intercepted between the axis is

The length of the portion of the tangent at any point on the curve x2/3 + y2/3 = a2/3 intercepted between the axis is

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The equation of the tangent to the curve x2 + 2y = 8 which is the perpendicular to x – 2y + 1 = 0 is

For such questions, we should know the formula to find the tangent and slope of lines and curves.

The equation of the tangent to the curve x2 + 2y = 8 which is the perpendicular to x – 2y + 1 = 0 is

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For such questions, we should know the formula to find the tangent and slope of lines and curves.

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In an isosceles triangle the ends of the base are (2a, 0) and (0, a) and one side is parallel to x – axis. The third vertex is

In an isosceles triangle the ends of the base are (2a, 0) and (0, a) and one side is parallel to x – axis. The third vertex is

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If x + 2y + 3 = 0, x + 2y – 7 = 0 and 2x – y – 4 = 0 form the sides of square, the equation of the fourth side is

For such questions, we should know properties of square. We should know the formula to find distance between two parallel lines.

If x + 2y + 3 = 0, x + 2y – 7 = 0 and 2x – y – 4 = 0 form the sides of square, the equation of the fourth side is

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For such questions, we should know properties of square. We should know the formula to find distance between two parallel lines.

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The number of real values of k for which the lines x – 2y + 3 = 0, kx + 3y + 1 = 0 and 4x – ky + 2 = 0 are concurrent is

For such questions, we should know properties of concurrent lines.

The number of real values of k for which the lines x – 2y + 3 = 0, kx + 3y + 1 = 0 and 4x – ky + 2 = 0 are concurrent is

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For such questions, we should know properties of concurrent lines.

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The distance of the line 2x – 3y = 4 from the point (1, 1) in the direction of the line x + y = 1 is

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The mid points of the sides of a triangle are (5, 0), (5, 12) and (0, 12). The orthocentre of this triangle is

The mid points of the sides of a triangle are (5, 0), (5, 12) and (0, 12). The orthocentre of this triangle is

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The image of the point A (1, 2) by the line mirror y = x is the point B and the image of B by line mirror y = 0 is the point

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If y equals T a n to the power of negative 1 end exponent invisible function application open parentheses fraction numerator square root of 1 plus a to the power of 2 end exponent x to the power of 2 end exponent end root minus 1 over denominator a x end fraction close parentheses text  then  end text open parentheses 1 plus a to the power of 2 end exponent x to the power of 2 end exponent close parentheses y to the power of parallel to end exponent plus 2 a to the power of 2 end exponent x y to the power of ´ end exponent equals

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If y equals T a n to the power of negative 1 end exponent invisible function application open parentheses fraction numerator square root of 1 plus a to the power of 2 end exponent x to the power of 2 end exponent end root minus 1 over denominator a x end fraction close parentheses text  then  end text open parentheses 1 plus a to the power of 2 end exponent x to the power of 2 end exponent close parentheses y to the power of parallel to end exponent plus 2 a to the power of 2 end exponent x y to the power of ´ end exponent equals

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For such questions, we should know different trigonometric formulas. We should simplify the function first before finding derivatives.

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If y equals c o s to the power of negative 1 end exponent invisible function application open parentheses fraction numerator a to the power of 2 end exponent minus x to the power of 2 end exponent over denominator a to the power of 2 end exponent plus x to the power of 2 end exponent end fraction close parentheses plus s i n to the power of negative 1 end exponent invisible function application open parentheses fraction numerator 2 a x over denominator a to the power of 2 end exponent plus x to the power of 2 end exponent end fraction close parentheses text  then  end text fraction numerator d y over denominator d x end fraction equals

For such questions, we should know the formulas of inverse functions.

If y equals c o s to the power of negative 1 end exponent invisible function application open parentheses fraction numerator a to the power of 2 end exponent minus x to the power of 2 end exponent over denominator a to the power of 2 end exponent plus x to the power of 2 end exponent end fraction close parentheses plus s i n to the power of negative 1 end exponent invisible function application open parentheses fraction numerator 2 a x over denominator a to the power of 2 end exponent plus x to the power of 2 end exponent end fraction close parentheses text  then  end text fraction numerator d y over denominator d x end fraction equals

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For such questions, we should know the formulas of inverse functions.

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