Maths-
General
Easy

Question

The image of the point A (1, 2) by the line mirror y = x is the point B and the image of B by line mirror y = 0 is the point

  1. (1, -2)    
  2. (0, 0)    
  3. (2, -1)    
  4. None    

The correct answer is: (2, -1)

Related Questions to study

General
Maths-

If y equals T a n to the power of negative 1 end exponent invisible function application open parentheses fraction numerator square root of 1 plus a to the power of 2 end exponent x to the power of 2 end exponent end root minus 1 over denominator a x end fraction close parentheses text  then  end text open parentheses 1 plus a to the power of 2 end exponent x to the power of 2 end exponent close parentheses y to the power of parallel to end exponent plus 2 a to the power of 2 end exponent x y to the power of ´ end exponent equals

For such questions, we should know different trigonometric formulas. We should simplify the function first before finding derivatives.

If y equals T a n to the power of negative 1 end exponent invisible function application open parentheses fraction numerator square root of 1 plus a to the power of 2 end exponent x to the power of 2 end exponent end root minus 1 over denominator a x end fraction close parentheses text  then  end text open parentheses 1 plus a to the power of 2 end exponent x to the power of 2 end exponent close parentheses y to the power of parallel to end exponent plus 2 a to the power of 2 end exponent x y to the power of ´ end exponent equals

Maths-General

For such questions, we should know different trigonometric formulas. We should simplify the function first before finding derivatives.

General
Maths-

If y equals c o s to the power of negative 1 end exponent invisible function application open parentheses fraction numerator a to the power of 2 end exponent minus x to the power of 2 end exponent over denominator a to the power of 2 end exponent plus x to the power of 2 end exponent end fraction close parentheses plus s i n to the power of negative 1 end exponent invisible function application open parentheses fraction numerator 2 a x over denominator a to the power of 2 end exponent plus x to the power of 2 end exponent end fraction close parentheses text  then  end text fraction numerator d y over denominator d x end fraction equals

For such questions, we should know the formulas of inverse functions.

If y equals c o s to the power of negative 1 end exponent invisible function application open parentheses fraction numerator a to the power of 2 end exponent minus x to the power of 2 end exponent over denominator a to the power of 2 end exponent plus x to the power of 2 end exponent end fraction close parentheses plus s i n to the power of negative 1 end exponent invisible function application open parentheses fraction numerator 2 a x over denominator a to the power of 2 end exponent plus x to the power of 2 end exponent end fraction close parentheses text  then  end text fraction numerator d y over denominator d x end fraction equals

Maths-General

For such questions, we should know the formulas of inverse functions.

General
Maths-

If y equals s i n invisible function application 2 x s i n invisible function application 3 x s i n invisible function application 4 x text  then  end text y to the power of parallel to end exponent equals

For such questions, we should know different formulas.

If y equals s i n invisible function application 2 x s i n invisible function application 3 x s i n invisible function application 4 x text  then  end text y to the power of parallel to end exponent equals

Maths-General

For such questions, we should know different formulas.

parallel
General
Maths-

fraction numerator d over denominator d x end fraction open curly brackets Tan to the power of negative 1 end exponent invisible function application open parentheses fraction numerator square root of 1 plus x to the power of 2 end exponent end root minus 1 over denominator x end fraction close parentheses close curly brackets equals

For such questions, we will use different formulas.

fraction numerator d over denominator d x end fraction open curly brackets Tan to the power of negative 1 end exponent invisible function application open parentheses fraction numerator square root of 1 plus x to the power of 2 end exponent end root minus 1 over denominator x end fraction close parentheses close curly brackets equals

Maths-General

For such questions, we will use different formulas.

General
Maths-

The length of the perpendicular from the incentre of the triangle formed by the axes and the line fraction numerator x over denominator 3 end fraction plus fraction numerator y over denominator 4 end fraction equals 1 to the hypotenuse is

The length of the perpendicular from the incentre of the triangle formed by the axes and the line fraction numerator x over denominator 3 end fraction plus fraction numerator y over denominator 4 end fraction equals 1 to the hypotenuse is

Maths-General
General
Maths-

If theta is the angle between two adjacent sides of a parallelogram and p, q are the distances between the parallel sides, then the area of the parallelogram

If theta is the angle between two adjacent sides of a parallelogram and p, q are the distances between the parallel sides, then the area of the parallelogram

Maths-General
parallel
General
Maths-

fraction numerator d over denominator d x end fraction open parentheses fraction numerator a x plus b over denominator c x plus d end fraction close parentheses equals

For such questions, we should know how to use u by v method.

fraction numerator d over denominator d x end fraction open parentheses fraction numerator a x plus b over denominator c x plus d end fraction close parentheses equals

Maths-General

For such questions, we should know how to use u by v method.

General
Maths-

fraction numerator d over denominator d x end fraction open parentheses e to the power of x to the power of 2 end exponent end exponent a to the power of x end exponent close parentheses equals

For such questions, we should know u.v method.

fraction numerator d over denominator d x end fraction open parentheses e to the power of x to the power of 2 end exponent end exponent a to the power of x end exponent close parentheses equals

Maths-General

For such questions, we should know u.v method.

General
Maths-

fraction numerator d over denominator d x end fraction open parentheses Tan to the power of negative 1 end exponent invisible function application square root of fraction numerator 1 minus c o s invisible function application x over denominator 1 plus c o s invisible function application x end fraction end root close parentheses equals

We should know different formulas to solve such questions.

fraction numerator d over denominator d x end fraction open parentheses Tan to the power of negative 1 end exponent invisible function application square root of fraction numerator 1 minus c o s invisible function application x over denominator 1 plus c o s invisible function application x end fraction end root close parentheses equals

Maths-General

We should know different formulas to solve such questions.

parallel
General
Maths-

fraction numerator d over denominator d x end fraction open parentheses Tan to the power of negative 1 end exponent invisible function application open parentheses fraction numerator a minus x over denominator 1 plus infinity x end fraction close parentheses close parentheses equals

For such questions, we should know different formulas.

fraction numerator d over denominator d x end fraction open parentheses Tan to the power of negative 1 end exponent invisible function application open parentheses fraction numerator a minus x over denominator 1 plus infinity x end fraction close parentheses close parentheses equals

Maths-General

For such questions, we should know different formulas.

General
Maths-

fraction numerator d over denominator d x end fraction open parentheses cosec to the power of negative 1 end exponent invisible function application open parentheses e to the power of 2 x plus 1 end exponent close parentheses close parentheses equals

For such questions, we should know different formulas.

fraction numerator d over denominator d x end fraction open parentheses cosec to the power of negative 1 end exponent invisible function application open parentheses e to the power of 2 x plus 1 end exponent close parentheses close parentheses equals

Maths-General

For such questions, we should know different formulas.

General
Maths-

fraction numerator d over denominator d x end fraction open parentheses fraction numerator sin invisible function application x over denominator 1 plus c o s invisible function application x end fraction close parentheses equals

The alternate method to solve this will be using u by method. It is method used in differentiation when we have a condition of numerator and denominator.

fraction numerator d over denominator d x end fraction open parentheses fraction numerator sin invisible function application x over denominator 1 plus c o s invisible function application x end fraction close parentheses equals

Maths-General

The alternate method to solve this will be using u by method. It is method used in differentiation when we have a condition of numerator and denominator.

parallel
General
Maths-

Locus of the foot of perpendicular fr om (-2,3) to a variable line with x intercept 2 is

Locus of the foot of perpendicular fr om (-2,3) to a variable line with x intercept 2 is

Maths-General
General
Maths-

Vertices of a triangle are (4, 3) , left parenthesis 5 blank s i n blank capital theta comma blank 5 blank c o s blank capital theta right parenthesis comma left parenthesis 5 blank c o s blank capital theta comma blank minus 5 blank s i n blank capital theta right parenthesis Then the locus of the orthocenter is

Vertices of a triangle are (4, 3) , left parenthesis 5 blank s i n blank capital theta comma blank 5 blank c o s blank capital theta right parenthesis comma left parenthesis 5 blank c o s blank capital theta comma blank minus 5 blank s i n blank capital theta right parenthesis Then the locus of the orthocenter is

Maths-General
General
Maths-

A line through A(-5, -4) meets the line x+3y+2=0, 2x+y+4=0 and x-y-5=0 at B comma C and D respectively. If left parenthesis fraction numerator 15 over denominator A B end fraction right parenthesis to the power of 2 end exponent plus left parenthesis fraction numerator 10 over denominator A C end fraction right parenthesis to the power of 2 end exponent equals left parenthesis fraction numerator 6 over denominator A D end fraction right parenthesis to the power of 2 end exponent then the equation of the line is

A line through A(-5, -4) meets the line x+3y+2=0, 2x+y+4=0 and x-y-5=0 at B comma C and D respectively. If left parenthesis fraction numerator 15 over denominator A B end fraction right parenthesis to the power of 2 end exponent plus left parenthesis fraction numerator 10 over denominator A C end fraction right parenthesis to the power of 2 end exponent equals left parenthesis fraction numerator 6 over denominator A D end fraction right parenthesis to the power of 2 end exponent then the equation of the line is

Maths-General
parallel

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