Question
The number of real values of k for which the lines x – 2y + 3 = 0, kx + 3y + 1 = 0 and 4x – ky + 2 = 0 are concurrent is
- 0
- 1
- 2
- infinite
Hint:
We are given equation of three lines. We have to find the value of K such that the given lines are concurrent. It means they pass through single point. For lines to be concurrent, the determinant of their coefficients should be zero. We have to find the real values of K.
.
The correct answer is: 0
The given lines are as follows
x - 2y + 3 = 0
Kx + 3y + 1 = 0
4x - ky + 2 = 0
We will take the determinant of the coefficients

To find the roots we will use the formula to solve quadratic equations.

we will first find the value of b2 - 4ac
b2 - 4ac = (-5)2 - 4(3)(38)
= 25 - 456
= -431
So, b - 4ac < 0
It doesn't have any real values. As, the value under is negative.
The answer is zero.
For such questions, we should know properties of concurrent lines.
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If 
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If 
For such questions, we should know different trigonometric formulas. We should simplify the function first before finding derivatives.
If 
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If 
For such questions, we should know the formulas of inverse functions.
If 
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If 
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The length of the perpendicular from the incentre of the triangle formed by the axes and the line
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If
is the angle between two adjacent sides of a parallelogram and p, q are the distances between the parallel sides, then the area of the parallelogram
If
is the angle between two adjacent sides of a parallelogram and p, q are the distances between the parallel sides, then the area of the parallelogram
For such questions, we should know how to use u by v method.
For such questions, we should know how to use u by v method.
For such questions, we should know u.v method.
For such questions, we should know u.v method.
We should know different formulas to solve such questions.
We should know different formulas to solve such questions.
For such questions, we should know different formulas.
For such questions, we should know different formulas.
For such questions, we should know different formulas.
For such questions, we should know different formulas.
The alternate method to solve this will be using u by method. It is method used in differentiation when we have a condition of numerator and denominator.
The alternate method to solve this will be using u by method. It is method used in differentiation when we have a condition of numerator and denominator.