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Chemistry-

General

Easy

Question

A black colored compound (A)on reaction with diluteH₂SO₄ gives a gas(B) which on passing in a solution ofan acid (C) gives a white turbidity (D). Gas (B) when placed nan acidified solution of a compound(E)gives a precipitate(F)solubleindiluteHNO₃.Afterboilingthissolution,whenanexcessofNH₄OHisadded,bluecoloredcompound(G) is formed. To this solution on additionofCH₃COOHandaqueous K₄[Fe(CN)₆],a chocolate precipitate(H)isobtained. On addition of an aqueous solution ofBaCl₂ to an aqueous solutionofE,awhitepptinsolubleinHNO₃isobtained. Identify C:

CH₃COOH
HNO₃
H₂S
CuS

The correct answer is: HNO₃

Related Questions to study

A black colored compound(A)on reaction with dil. H₂SO₄ gives a gas(B)which onpassingin a solution of anacid (C) gives a white turbidity (D). Gas (B)when passed in an acidified solution of a compound(E) gives a black precipitate (F) which is soluble in hot concentrated (C).After boiling this solution whene xcess of ammonia solution is added, a blue colored compound (G) is formed. To the solution of(E), onaddition of acetic acid and aqueous potassium ferrocyanide, a chocolate brown precipitate (H) is formed.OnadditionofanaqueoussolutionofBaCl₂toan aqueoussolutionof(E),white precipitate insoluble in HNO₃isobtained. To which of the following property, will the compound(E)respond?

A black colored compound(A)on reaction with dil. H₂SO₄ gives a gas(B)which onpassingin a solution of anacid (C) gives a white turbidity (D). Gas (B)when passed in an acidified solution of a compound(E) gives a black precipitate (F) which is soluble in hot concentrated (C).After boiling this solution whene xcess of ammonia solution is added, a blue colored compound (G) is formed. To the solution of(E), onaddition of acetic acid and aqueous potassium ferrocyanide, a chocolate brown precipitate (H) is formed.OnadditionofanaqueoussolutionofBaCl₂toan aqueoussolutionof(E),white precipitate insoluble in HNO₃isobtained. To which of the following property, will the compound(E)respond?

Chemistry-General

The maximum value of $left parenthesis log invisible function application x right parenthesis divided by x$ is

The maximum value of $left parenthesis log invisible function application x right parenthesis divided by x$ is

The abscissa if points $P blank$ and $Q$ on the curve $y equals e to the power of x end exponent plus blank e to the power of negative x end exponent$ such that tangents at $P$ and $Q$ make $60$ with the $x$ -axis

The abscissa if points $P blank$ and $Q$ on the curve $y equals e to the power of x end exponent plus blank e to the power of negative x end exponent$ such that tangents at $P$ and $Q$ make $60$ with the $x$ -axis

parallel

If $f open parentheses x close parentheses equals x e to the power of x left parenthesis x minus 1 right parenthesis end exponent$ , then $f left parenthesis x right parenthesis$ is

If $f open parentheses x close parentheses equals x e to the power of x left parenthesis x minus 1 right parenthesis end exponent$ , then $f left parenthesis x right parenthesis$ is

At what points of curve $y equals fraction numerator 2 over denominator 3 end fraction x to the power of 3 end exponent plus fraction numerator 1 over denominator 2 end fraction x to the power of 2 end exponent$ , the tangent makes the equal angle with the axis?

At what points of curve $y equals fraction numerator 2 over denominator 3 end fraction x to the power of 3 end exponent plus fraction numerator 1 over denominator 2 end fraction x to the power of 2 end exponent$ , the tangent makes the equal angle with the axis?

$f open parentheses x close parentheses equals 4 tan invisible function application x minus tan to the power of 2 end exponent invisible function application x plus tan to the power of 3 end exponent invisible function application x comma blank x not equal to n pi plus fraction numerator pi over denominator 2 end fraction$

$f open parentheses x close parentheses equals 4 tan invisible function application x minus tan to the power of 2 end exponent invisible function application x plus tan to the power of 3 end exponent invisible function application x comma blank x not equal to n pi plus fraction numerator pi over denominator 2 end fraction$

parallel

The fuel charges for running a train are proportional to the square of the speed generated in km per hour, and the cost is Rs. 48 at 16 km per hour. If the fixed charges amount to Rs. 300 per hour, the most economical speed is

The fuel charges for running a train are proportional to the square of the speed generated in km per hour, and the cost is Rs. 48 at 16 km per hour. If the fixed charges amount to Rs. 300 per hour, the most economical speed is

Suppose that $f$ is a polynomial of degree 3 and that $f to the power of ´ ´ end exponent left parenthesis x right parenthesis not equal to 0$ at any of the stationary point. Then

Suppose that $f$ is a polynomial of degree 3 and that $f to the power of ´ ´ end exponent left parenthesis x right parenthesis not equal to 0$ at any of the stationary point. Then

Let $f open parentheses x close parentheses equals cos invisible function application pi x plus 10 x plus 3 x to the power of 2 end exponent plus x to the power of 3 end exponent comma blank minus 2 less or equal than x less or equal than 3$ . The absolute minimum value of $f left parenthesis x right parenthesis$ is

Let $f open parentheses x close parentheses equals cos invisible function application pi x plus 10 x plus 3 x to the power of 2 end exponent plus x to the power of 3 end exponent comma blank minus 2 less or equal than x less or equal than 3$ . The absolute minimum value of $f left parenthesis x right parenthesis$ is

parallel

Let $f open parentheses x close parentheses equals open curly brackets table row cell x plus 2 comma blank minus 1 less or equal than x less than 0 end cell row cell 1 comma blank x equals 0 blank end cell row cell fraction numerator x over denominator 2 end fraction comma blank 0 less than x less or equal than 1 end cell end table close$ Then on $left square bracket negative 1 comma blank 1 right square bracket$ , this function has

Let $f open parentheses x close parentheses equals open curly brackets table row cell x plus 2 comma blank minus 1 less or equal than x less than 0 end cell row cell 1 comma blank x equals 0 blank end cell row cell fraction numerator x over denominator 2 end fraction comma blank 0 less than x less or equal than 1 end cell end table close$ Then on $left square bracket negative 1 comma blank 1 right square bracket$ , this function has

If $ϕ left parenthesis x right parenthesis$ is a polynomial function and $ϕ to the power of ´ end exponent open parentheses x close parentheses greater than ϕ open parentheses x close parentheses comma blank for all blank x greater or equal than 1$ and $ϕ open parentheses 1 close parentheses equals 0$ , then

If $ϕ left parenthesis x right parenthesis$ is a polynomial function and $ϕ to the power of ´ end exponent open parentheses x close parentheses greater than ϕ open parentheses x close parentheses comma blank for all blank x greater or equal than 1$ and $ϕ open parentheses 1 close parentheses equals 0$ , then

If $f open parentheses x close parentheses equals x plus sin invisible function application x semicolon g open parentheses x close parentheses equals e to the power of negative x end exponent semicolon u equals square root of c plus 1 end root minus square root of c semicolon v equals square root of c minus square root of c minus 1 end root semicolon left parenthesis c greater than 1 right parenthesis$ , then

If $f open parentheses x close parentheses equals x plus sin invisible function application x semicolon g open parentheses x close parentheses equals e to the power of negative x end exponent semicolon u equals square root of c plus 1 end root minus square root of c semicolon v equals square root of c minus square root of c minus 1 end root semicolon left parenthesis c greater than 1 right parenthesis$ , then

parallel

The value of $c$ in Lagrange’s theorem for the function $f open parentheses x close parentheses equals log invisible function application sin invisible function application x$ in the interval $left square bracket divided by 6 comma blank 5 divided by 6 right square bracket$

The value of $c$ in Lagrange’s theorem for the function $f open parentheses x close parentheses equals log invisible function application sin invisible function application x$ in the interval $left square bracket divided by 6 comma blank 5 divided by 6 right square bracket$

Let $f left parenthesis x right parenthesis$ be a function such that $f to the power of ´ end exponent open parentheses x close parentheses equals log subscript 1 divided by 3 end subscript invisible function application left square bracket log subscript 3 end subscript invisible function application left parenthesis sin invisible function application x plus a right parenthesis right square bracket$ . If $f left parenthesis x right parenthesis$ is decreasing for all real values of $x$ , then

Let $f left parenthesis x right parenthesis$ be a function such that $f to the power of ´ end exponent open parentheses x close parentheses equals log subscript 1 divided by 3 end subscript invisible function application left square bracket log subscript 3 end subscript invisible function application left parenthesis sin invisible function application x plus a right parenthesis right square bracket$ . If $f left parenthesis x right parenthesis$ is decreasing for all real values of $x$ , then

The volume of the greatest cylinder which can be inscribed in a cone of height 30 cm and semi-vertical angle $30 degree$ is

The volume of the greatest cylinder which can be inscribed in a cone of height 30 cm and semi-vertical angle $30 degree$ is

parallel

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