Mathematics
Grade9
Easy

Question

A triangle has sizes measuring 11 cm, 16 cm, and 16 cm. A similar triangle has sides measuring x cm, 24 cm, and 24 cm. Find x?

  1. x = 19 cm
  2. x = 24 cm
  3. x = 3 cm
  4. x = 16.5 cm

hintHint:

We are given the lengths of two triangles. They are similar triangles. For one triangle we are given all three sides. For the second triangle we are only given two sides. We are asked to find the value of the third side. To solve this question, we will use the properties of the similar triangles.

The correct answer is: x = 16.5 cm


    Let the first triangle be ABC and second triangle be PQR.
    The length of the sides are as follows:
    For ∆ABC
    AB = 11 cm
    BC = 16 cm
    AC = 16 cm
    For ∆PQR
    PQ = x cm
    QR = 24 cm
    PR = 24 cm
    We are given that the triangles are similar. Similar triangles have same shape but their sizes are different.
    The ratio of the sides of the similar triangles is equal. So, to find the side we will take the ratio of the sides.
    Let’s take the ratio of the sides of the above triangles.    .     
    .        fraction numerator A B over denominator P Q end fraction equals fraction numerator B C over denominator Q R end fraction space equals fraction numerator A C over denominator P R end fraction
11 over x space equals 16 over 24 equals space 16 over 24
    Let's solve for x. We will just take two ratios.
    ...       11 over x equals 16 over 24
r e a r r a n g i n g space f o r space x
x space equals space fraction numerator 24 space cross times space 11 over denominator 16 end fraction
space space space equals space 16.5 space
    x = 16.5 cm
    Therefore, the value of x = 16.5 cm.

    ,

    We should know about different properties of similar triangles. We have to be careful about which sides to choose for the ratio.

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