Mathematics
Grade-8
Easy

Question

Justin proposed an offer of chocolate to whoever guesses the number he chose correctly. He gives them a clue:” Five times the number is 5 more than the number.” The number Justin chose is

  1. 5 over 4
  2. 1
  3. 4 over 5
  4. Infinitely many solutions

hintHint:

An equation has a constant, variable and an equal to sign. It has two sides LHS and RHS. A linear equation in one variable is equation with only one variable and in which the highest degree is 1. Here, we have to find the value of unknown value, by operating both sides with the same number so that the equation will be balanced.

The correct answer is: 5 over 4


In the question the clue given by Justin is five times the number is 5 more than the number.
We have to find the number chosen by Justin.
Step 1: Convert the word problem into numerical problem.
Let the number chosen by Justin be x.
So, the equation will be
5x= 5+x
Bring all the terms containing variables in one side by operating same numbers on both sides to balance the equation.
Step 2: Subtract x on both sides.
rightwards double arrow5x-x= 5+x-x
rightwards double arrow5x-x= 5
rightwards double arrow4x=5
Step 3: Divide both sides by 4.
rightwards double arrow fraction numerator 4 x over denominator 4 end fraction equals 5 over 4
rightwards double arrow x equals 5 over 4
So, the number chosen by is 5 over 4.
Therefore, the correct option is c, i.e., 5 over 4.

Like terms are the terms having same variable of same power in which the coefficient may not be the same whereas unlike terms are the terms which don't have same variable. Addition and subtraction are possible in like terms but not in unlike terms.

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