Question
What will be the new position of the given point (9, -4) after translation of 6 units right and 3 units down?
- (13, 7)
- (15, -7)
- (3, 15)
- (3, -15)
Hint:
On the X-axis,
Positive translation – Shifting to the right (x + h)
On the Y-axis,
Negative translation – Shifting vertically downward (y - k)
The correct answer is: (15, -7)
On the X-axis,
Positive translation – Shifting to the right (x + h)
Negative translation – Shifting to the left (x - h)
On the Y-axis,
Positive translation – Shifting vertically upward (y + k)
Negative translation – Shifting vertically downward (y - k)
→ X = 9 + 6 = 15 and y = - 4 -3 = - 7
Related Questions to study
What will be the new position of the given point (8, 3) after translation of 3 units left and 2 units up?
What will be the new position of the given point (8, 3) after translation of 3 units left and 2 units up?
Graph a quadrilateral whose vertices are A(-3, -2), B(-5, -2), C(-6, 1), and D(-3, 2). Graph ABCD quadrilateral and its image when rotated 180o about the origin
Graph a quadrilateral whose vertices are A(-3, -2), B(-5, -2), C(-6, 1), and D(-3, 2). Graph ABCD quadrilateral and its image when rotated 180o about the origin
Graph a quadrilateral whose vertices are A(-3, -2), B(-5, -2), C(-6, 1), and D(-3, 2). Graph ABCD quadrilateral and its image when rotated 90o about the origin
Graph a quadrilateral whose vertices are A(-3, -2), B(-5, -2), C(-6, 1), and D(-3, 2). Graph ABCD quadrilateral and its image when rotated 90o about the origin
Graph a triangle ABC with vertices A(2, 1), B(4, 4), and C(8, 0). Rotate the triangle 270o about the origin.
Graph a triangle ABC with vertices A(2, 1), B(4, 4), and C(8, 0). Rotate the triangle 270o about the origin.
Graph a triangle LMN with vertices L(-5, -3), M(-3, -5), and N(0, -1). Rotate the triangle 180o about the origin.
Graph a triangle LMN with vertices L(-5, -3), M(-3, -5), and N(0, -1). Rotate the triangle 180o about the origin.
Find the image coordinate of the figure w.r.t 270o rotation about the origin.
Find the image coordinate of the figure w.r.t 270o rotation about the origin.
Find the image vertices of the line w.r.t 90o rotation about the origin.
Find the image vertices of the line w.r.t 90o rotation about the origin.
Find the coordinate of the point and its image point w.r.t 180o rotation about the origin.
Find the coordinate of the point and its image point w.r.t 180o rotation about the origin.
When a point (2, -4) is rotated counterclockwise about the origin. Find the coordinate after the rotation of 90o rotation.
When a point (2, -4) is rotated counterclockwise about the origin. Find the coordinate after the rotation of 90o rotation.
If you can rotate a figure more than 360o, then the effect is the __________as rotating the figure by the angle minus 360o.
If you can rotate a figure more than 360o, then the effect is the __________as rotating the figure by the angle minus 360o.
Graph a triangle ABC with vertices A(2, 1), B(4, 4), and C(8, 0). Rotate the triangle 180o about the origin.
Given, the vertices of a triangle ABC with vertices A(2, 1), B(4, 4), and C(8, 0).
For a rotation of 180 degrees, coordinate rule (a, b) → (-a, -b).
A(2, 1) → A’(-2, -1)
B(4, 4) → B’(-4, -4)
C(8, 0) → C’(-8, 0)
Now, graph the triangle A’B’C’.
Graph a triangle ABC with vertices A(2, 1), B(4, 4), and C(8, 0). Rotate the triangle 180o about the origin.
Given, the vertices of a triangle ABC with vertices A(2, 1), B(4, 4), and C(8, 0).
For a rotation of 180 degrees, coordinate rule (a, b) → (-a, -b).
A(2, 1) → A’(-2, -1)
B(4, 4) → B’(-4, -4)
C(8, 0) → C’(-8, 0)
Now, graph the triangle A’B’C’.
Graph a triangle LMN with vertices L(-5, -3), M(-3, -5), and N(0, -1). Rotate the triangle 90 about the origin.
Given, the vertices of a triangle ABC with vertices L(-5, -3), M(-3, -5), and N(0, -1).
For a rotation of 90 degrees, coordinate rule (a, b) → (-b, a).
L(-5, -3) → L’(3, -5)
M(-3, -5) → M’(5, -3)
N(0, -1) → N’(1, 0)
Now, graph the triangle L’M’N’.
Graph a triangle LMN with vertices L(-5, -3), M(-3, -5), and N(0, -1). Rotate the triangle 90 about the origin.
Given, the vertices of a triangle ABC with vertices L(-5, -3), M(-3, -5), and N(0, -1).
For a rotation of 90 degrees, coordinate rule (a, b) → (-b, a).
L(-5, -3) → L’(3, -5)
M(-3, -5) → M’(5, -3)
N(0, -1) → N’(1, 0)
Now, graph the triangle L’M’N’.
Find the image coordinates of the figure w.r.t 180o rotation about the origin.
Given coordinates of the figure, A(1, 2), B(5, 2), and C(3, 5).
For a rotation of 180 degrees, coordinate rule (a, b) → (-a, -b).
A(1, 2) → A’(-1, -2)
B(5, 2) → B’(-5, -2)
C(3, 5) → C’(-3, -5)
Image coordinates of the figure are A’(-1, -2), B’(-5, -2), and C’(-3, -5).
Find the image coordinates of the figure w.r.t 180o rotation about the origin.
Given coordinates of the figure, A(1, 2), B(5, 2), and C(3, 5).
For a rotation of 180 degrees, coordinate rule (a, b) → (-a, -b).
A(1, 2) → A’(-1, -2)
B(5, 2) → B’(-5, -2)
C(3, 5) → C’(-3, -5)
Image coordinates of the figure are A’(-1, -2), B’(-5, -2), and C’(-3, -5).
Find the image vertices of the line w.r.t 90o rotation about the origin.
Coordinate of the line AB, A= (1, 2) and B= (5, 2)
For a rotation of 90, coordinate rule (a, b) → (-b, a).
A(1, 2) → A’(-2, 1)
B(5, 2) → B’(-2, 5)
Image vertices of the line AB are A’(-2, 1) and B’(-2, 5).
Find the image vertices of the line w.r.t 90o rotation about the origin.
Coordinate of the line AB, A= (1, 2) and B= (5, 2)
For a rotation of 90, coordinate rule (a, b) → (-b, a).
A(1, 2) → A’(-2, 1)
B(5, 2) → B’(-2, 5)
Image vertices of the line AB are A’(-2, 1) and B’(-2, 5).
Find the coordinate of the point and its image point w.r.t 270o rotation about the origin.
Coordinate of point V = (-3, -2)
For a rotation of 270 degrees, coordinate rule (a, b) → (b, -a).
V(-3, -2) → V’(-2, 3)
The coordinate V(-3, -2) and its image V’(-2, 3).
Find the coordinate of the point and its image point w.r.t 270o rotation about the origin.
Coordinate of point V = (-3, -2)
For a rotation of 270 degrees, coordinate rule (a, b) → (b, -a).
V(-3, -2) → V’(-2, 3)
The coordinate V(-3, -2) and its image V’(-2, 3).
