Question
A and B can do a piece of work in 40 days while B and C can do it in 60 days. If A is twice as good a workman as C, then C alone will do the work in
- 120 days
- 100 days
- 80 days
- 24 days
Hint:
The given question is about work and efficiency. A and B can do a work together in 40 days. B and C can do a work together in 60 days. A is twice efficient than C. We have to find the work done by C alone.
The correct answer is: 100 days
Let the work done by A, B and C per day be denoted as a, b and c respectively.
A and B does the work in 40 days.
So, work done by them in 1 day is given by
a + b = …(1)
B and C does the work in 60 days.
So, work done by them in 1 day is given by
c + b = …(2)
Let the number of days required by A = x
It is given that A is twice efficient than C
The number of days required by C = 2x
So, a =
c =
We will subtract equation (2) from (1)
Substituting the values of a and c we get,
So, 2x = 120
So, the days required by C are 120 days.
For such questions, we should know the concept of work and efficiency.
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