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Maths-

General

Easy

Question

If 4x²+ bx + 9 = 0, where b is a constant, has exactly one solution, what is a possible value of b?

72
36
12
6

The correct answer is: 12

Step by step explanation:
Given:
Equation: 4x²+ bx + 9 = 0
Step 1:
Compare given equation with general equation.
ax² + bx + c = 0
By comparing we will get
⇒ a = 4, b = b and c = 9
Step 2:
Find the discriminant i. e D.
D = b² - 4ac
⇒ D = b² - 4 (4) (9)
⇒ D = b² - 144
Step 3:
Use condition for equal roots
We know that for D = 0, equation has equal and real roots
∴ D = 0
⇒ b² - 144 = 0
⇒ b² = 144
$not stretchy rightwards double arrow straight b equals square root of 144$
$not stretchy rightwards double arrow straight b equals plus-or-minus 12$
∴ b = $plus-or-minus$ 12
Hence, the value of b will be 12 as - 12 is not in the option.

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