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Maths-

General

Easy

Question

If $fraction numerator b over denominator c plus a end fraction plus fraction numerator c over denominator a plus b end fraction equals 1$ then

$A = 60^{\circ}$
$B = 60^{\circ}$
$C = 60^{\circ}$
$A = 90^{\circ}$

hint Hint:

To find the value of angle A we will solve the equation using the cosine formula .

The correct answer is: $A equals 60 to the power of ring operator$

In $triangle$ ABC,
$fraction numerator c over denominator a plus b end fraction plus fraction numerator b over denominator c plus a end fraction equals 1 rightwards double arrow fraction numerator c left parenthesis c plus a right parenthesis plus b left parenthesis a plus b right parenthesis over denominator left parenthesis a plus b right parenthesis left parenthesis c plus a right parenthesis end fraction equals 1 rightwards double arrow c squared plus a c plus a b plus b squared equals left parenthesis a plus b right parenthesis left parenthesis a plus c right parenthesis rightwards double arrow c squared plus a c plus a b plus b squared equals a squared plus a c plus a b plus b c rightwards double arrow c squared plus b squared minus a squared equals b c rightwards double arrow 2. b c. cos A equals b c space space space open square brackets b y space cos i n e space f o r m u l a close square brackets rightwards double arrow 2 cos A equals 1 rightwards double arrow cos A equals 1 half rightwards double arrow A equals 60 degree$

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