Maths-
General
Easy
Question
The probability of the simultaneous occurrence of two events A and B is p. If the probability that exactly one of A,B occurs is q, then
+ P B ' = 2 + 2 q - p '/>
+ P B ' = 2 - 2 p - q '/>
-
∩ B = 1 - p - q '/>
The correct answer is:
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Chemistry-
The removal of two atoms or groups, one generally hydrogen and the other a leaving group resulting in the formation of unsaturated compound is known as elimination reaction.
In (elimination) reactions, the bond is broken heterolytic ally (in step 1) to form a carbocation (as in reaction) in which ) is lost (rate determining step). The carbocation (in step 2) loses a proton from the -carbon atom by a base (nucleophile) to form an alkene. reaction is favoured in compounds in which the leaving group is at secondary or tertiary position. In formed simultaneously. reactions occur in one step through a transition state.
reactions are most common in haloalkanes (particularly, ) and better the leaving group higher is the reaction. In reactions, both the leaving groups should be antiplanar.
cb (Elimination unimolecular conjugate base) reaction involves the removal of proton by. a conjugate base (step 1) to produce carbanion which loses a leaving group to form an alkene (step 2) and is a slow step.
2-Bromobutane on heating with concentrated solution of alcoholic KOH gives major product as:
The removal of two atoms or groups, one generally hydrogen and the other a leaving group resulting in the formation of unsaturated compound is known as elimination reaction.
In (elimination) reactions, the bond is broken heterolytic ally (in step 1) to form a carbocation (as in reaction) in which ) is lost (rate determining step). The carbocation (in step 2) loses a proton from the -carbon atom by a base (nucleophile) to form an alkene. reaction is favoured in compounds in which the leaving group is at secondary or tertiary position. In formed simultaneously. reactions occur in one step through a transition state.
reactions are most common in haloalkanes (particularly, ) and better the leaving group higher is the reaction. In reactions, both the leaving groups should be antiplanar.
cb (Elimination unimolecular conjugate base) reaction involves the removal of proton by. a conjugate base (step 1) to produce carbanion which loses a leaving group to form an alkene (step 2) and is a slow step.
2-Bromobutane on heating with concentrated solution of alcoholic KOH gives major product as:
Chemistry-General