Physics
Grade-9
Easy
Question
A 47 Ω resistor, a 22 Ω resistor, and a 10 Ω resistor are connected in parallel. The total resistance is approximately
- 6 Ω
- 1/6 Ω
- 3 Ω
- 1/3 Ω
Hint:
For resistors connected in parallel, the total resistance of circuit is equal to the sum of reciprocals of individual resistance of the resistors.
The correct answer is: 6 Ω
When a 47 Ω resistor, a 22 Ω resistor, and a 10 Ω resistor are connected in parallel, the total resistance is approximately 6Ω.
- The formula that can calculate the total resistance in a parallel circuit=
- Given, R1, R2, and R3 are 47Ω, 22Ω, and 10Ω respectively.
So, we can calculate
1/RT= 1/47+1/22+1/10
1/RT= 1/0.166= 6.02
RT= 6.024
- So the total resistance (RT) in the circuit is approx. 6 Ω.
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