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Physics-

General

Easy

Question

A cylindrical piston of mass M slides smoothly inside a long cylinder closed at one end, enclosing a certain mass of a gas. The cylinder is kept with its axis horizontal. If the piston is slightly compressed isothermally from its equilibrium position, it oscillates simple harmonically, the period of oscillation will be

T = $2 π$ $\sqrt{\frac{M h}{P A}}$
T = $2 π$ $\sqrt{\frac{M A}{P h}}$
T = $2 π$ $\sqrt{\frac{M}{P A h}}$
T = $2 π$ $\sqrt{M P h A}$

The correct answer is: T = $2 pi$ $square root of fraction numerator M h over denominator P A end fraction end root$

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