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Physics-

General

Easy

Question

If $stack A with rightwards arrow on top equals stack B with rightwards arrow on top comma$ then which of the following is not correct

$\hat{A} = \hat{B}$
$\hat{A} ∙ \hat{B} = A B$
$|\vec{A}| = |\vec{B}|$
$A \hat{B} || B \hat{A}$

The correct answer is: $stack A with hat on top bullet stack B with hat on top equals A B$

$stack A with hat on top bullet stack B with hat on top equals open parentheses 1 close parentheses open parentheses 1 close parentheses c o s 0 degree equals 1 not equal to A B$ .

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The horizontal range of an oblique projectile is equal to the distance through which a projectile has to fall freely from rest to acquire a velocity equal to the velocity of projection in magnitude. The angle of projection is

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Two bodies are thrown up at angles of $45 degree$ and $60 degree$ , respectively with the horizontal. If both bodies attain same vertical height , then the ratio of velocities with which these are thrown is

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parallel

A helicopter is flying horizontally at an altitude of 2 km with a speed of $100 blank m s to the power of negative 1 end exponent$ . A packet is dropped from it. The horizontal distance between the point where the packet is dropped and the point where it hits the ground is $left parenthesis g equals 10 blank m s to the power of negative 2 end exponent right parenthesis$

A helicopter is flying horizontally at an altitude of 2 km with a speed of $100 blank m s to the power of negative 1 end exponent$ . A packet is dropped from it. The horizontal distance between the point where the packet is dropped and the point where it hits the ground is $left parenthesis g equals 10 blank m s to the power of negative 2 end exponent right parenthesis$

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If the sides be a, b, c then $fraction numerator b minus c over denominator r subscript 1 end subscript end fraction$ + $fraction numerator c minus a over denominator r subscript 2 end subscript end fraction$ + $fraction numerator a minus b over denominator r subscript 3 end subscript end fraction$ =

If the sides be a, b, c then $fraction numerator b minus c over denominator r subscript 1 end subscript end fraction$ + $fraction numerator c minus a over denominator r subscript 2 end subscript end fraction$ + $fraction numerator a minus b over denominator r subscript 3 end subscript end fraction$ =

If the sides be a, b, c then (r + r1) tan $fraction numerator B minus C over denominator 2 end fraction$ + (r + r2) tan $fraction numerator C minus A over denominator 2 end fraction$ + (r+ r3) tan $fraction numerator A minus B over denominator 2 end fraction$ =

If the sides be a, b, c then (r + r1) tan $fraction numerator B minus C over denominator 2 end fraction$ + (r + r2) tan $fraction numerator C minus A over denominator 2 end fraction$ + (r+ r3) tan $fraction numerator A minus B over denominator 2 end fraction$ =

parallel

$open parentheses fraction numerator 1 over denominator r subscript 1 end subscript end fraction plus fraction numerator 1 over denominator r subscript 2 end subscript end fraction close parentheses$ $open parentheses fraction numerator 1 over denominator r subscript 3 end subscript end fraction plus fraction numerator 1 over denominator r subscript 1 end subscript end fraction close parentheses$ =

$open parentheses fraction numerator 1 over denominator r subscript 1 end subscript end fraction plus fraction numerator 1 over denominator r subscript 2 end subscript end fraction close parentheses$ $open parentheses fraction numerator 1 over denominator r subscript 3 end subscript end fraction plus fraction numerator 1 over denominator r subscript 1 end subscript end fraction close parentheses$ =

(r1 – r) (r2 – r) (r3 – r) =

(r1 – r) (r2 – r) (r3 – r) =

$fraction numerator 1 over denominator r subscript 1 end subscript superscript 2 end superscript end fraction$ + $fraction numerator 1 over denominator r subscript 2 end subscript superscript 2 end superscript end fraction$ + $fraction numerator 1 over denominator r subscript 3 end subscript superscript 2 end superscript end fraction$ + $fraction numerator 1 over denominator r subscript blank superscript 2 end superscript end fraction$ =

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parallel

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abc =

abc =

If the altitudes of a triangle be 3, 4, 6 then its in-radius is -

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parallel

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