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Physics-

General

Easy

Question

Two blocks each of mass m are connected with springs of force constant k. Initially springs are relaxed. Mass A is displaced to left and B is displaced towards right by same amount and released then time period of oscillation of any one block (Assume collision to be perfectly elastic)

$2 π \sqrt{\frac{m}{k}}$
$2 π \sqrt{\frac{m}{2 k}}$
$π \sqrt{\frac{m}{k}}$
$π \sqrt{\frac{m}{2 k}}$

The correct answer is: $pi square root of fraction numerator m over denominator k end fraction end root$

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