Question
In △ ABC, AB = x and BC = x + 1 . How many possible values are there for x if the perimeter of △ ABC is 14?
Hint:
Find the value of x using the sum of all sides equal to perimeter .
Here we get 2 cases if AB =AC (x side is repeated twice) and IF BC = AC(x + 1 side is repeated twice).
The correct answer is: x = 4 unit (or) x= 13/3 unit are two possible values of x.
ANS :- x = 4 unit (or) x= unit are two possible values of x.
Explanation :-
Step 1:- Find x if AB = AC (x side is repeated twice)
We get perimeter = x + x + x + 1
Given perimeter = 14 units
We get
∴ x = unit
Step 2:- Find x if BC = AC(x +1 side is repeated twice).
We get perimeter = x + 1 + x + 1 + x
Given perimeter = 14 units
We get
∴ x = 4 unit
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