Question
The area of parallelogram is p sq.cm and height is q cm. A second parallelogram has equal area but its base is r cm more than that of the first Obtain an expression in terms of p, q and r for the height of the second parallelogram.
Hint:
Find the area of the second parallelogram with the given condition and equal
it with the area of 1st parallelogram as they both have the same area (given). we get
the required relation .
The correct answer is: qp/(qr+p)
Ans :- 
Explanation :-
Given , area of 1st parallelogram = p sq.cm ; height = q cm .
Second parallelogram has equal area as 1st .
i.e Area of second parallelogram = p sq.cm
Base of 2nd parallelogram is r more than 1st parallelogram
Base of 2nd parallelogram = r+ Base of 1st parallelogram
Therefore, The height of second parallelogram in terms of p, q and r is 
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