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Area of a triangle whose vertices are left parenthesis a c o s invisible function application theta comma b s i n invisible function application theta right parenthesis comma left parenthesis negative a s i n invisible function application theta comma b c o s invisible function application theta right parenthesis text  and  end text left parenthesis negative a c o s invisible function application theta comma negative b s i n invisible function application theta right parenthesis is

  1. a b s i n invisible function application theta c o s invisible function application theta    
  2. a c o s invisible function application theta s i n invisible function application theta    
  3. fraction numerator 1 over denominator 2 end fraction a b    
  4. ab    

The correct answer is: ab

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If c o s to the power of negative 1 end exponent invisible function application x minus c o s to the power of negative 1 end exponent invisible function application fraction numerator y over denominator 2 end fraction equals alpha comma then 4 x to the power of 2 end exponent minus 4 x y c o s invisible function application alpha plus y to the power of 2 end exponent text end textis equal to-

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Maths-General

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The correct answer is choice 2

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Maths-General

Hence, the range of the given function is open parentheses negative straight pi over 2 comma straight pi over 2 close parentheses.

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Maths-

The range of the function f left parenthesis x right parenthesis equals fraction numerator 2 plus x over denominator 2 minus x end fraction comma x not equal to 2 text end textis-

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Maths-General

Hence, range of the given function will be R{1}

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