Physics-
General
Easy
Question
The minimum audible wavelength at room temperature is about
-
-
- 5 cm to 5 metres
- 20 mm
The correct answer is: 20 mm
Since maximum audible frequency is
Hence
Related Questions to study
physics-
Two open organ pipes gives 4 beats/sec when sounded together in their fundamental nodes. If the length of the pipe are and respectively, then the velocity of sound is :
Two open organ pipes gives 4 beats/sec when sounded together in their fundamental nodes. If the length of the pipe are and respectively, then the velocity of sound is :
physics-General
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An earthquake generates both transverse (s) and longitudinal (p) sound waves in the earth. The speed of S waves is about 4.5 m/s and that of waves is about 8.0 km/s. A seismograph records P and waves from an earthquake. The first pPwave arrives 4.0 min before the first S wave. The epicenter of the earthquake is located at a distance about
An earthquake generates both transverse (s) and longitudinal (p) sound waves in the earth. The speed of S waves is about 4.5 m/s and that of waves is about 8.0 km/s. A seismograph records P and waves from an earthquake. The first pPwave arrives 4.0 min before the first S wave. The epicenter of the earthquake is located at a distance about
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A source of sound is travelling towards a stationary observer. The frequency of sound heard by the observer is of three times the original frequency. The velocity of sound is vm/ sec. The speed of source will be
A source of sound is travelling towards a stationary observer. The frequency of sound heard by the observer is of three times the original frequency. The velocity of sound is vm/ sec. The speed of source will be
physics-General
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When the mass of a system is variable, a thrust force has to be applied on it in addition to all other forces acting on it. This thrust force is given by Here is the relative velocity with which the mass d m either enters or leaves the system. A car has total mass 50 kg. Gases are ejected from this backwards with relative velocity 20 m/s. The rate of ejection of gas is 2 kg/total mass of gas is 20 kg. Coefficient of friction between the car and road is = 0.1 Car will start moving after time t = . .. second:
When the mass of a system is variable, a thrust force has to be applied on it in addition to all other forces acting on it. This thrust force is given by Here is the relative velocity with which the mass d m either enters or leaves the system. A car has total mass 50 kg. Gases are ejected from this backwards with relative velocity 20 m/s. The rate of ejection of gas is 2 kg/total mass of gas is 20 kg. Coefficient of friction between the car and road is = 0.1 Car will start moving after time t = . .. second:
physics-General
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In an oblique collision component parallel to common tangent remains unchanged while along common normal direction, relative velocity of separation becomes e times the relative velocity of approach. A ball collides at B with velocity 10 m/s at 30° with vertical. There is a flag at A and a wall at C. Collision of ball with ground is perfectly inelastic (e = 0) and that with wall is elastic (e = 1). Given AB = BC = 10m. The ball will collide with the flag after time t = ....s
In an oblique collision component parallel to common tangent remains unchanged while along common normal direction, relative velocity of separation becomes e times the relative velocity of approach. A ball collides at B with velocity 10 m/s at 30° with vertical. There is a flag at A and a wall at C. Collision of ball with ground is perfectly inelastic (e = 0) and that with wall is elastic (e = 1). Given AB = BC = 10m. The ball will collide with the flag after time t = ....s
physics-General
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If net force on a system in a particular direction is zero (say in horizontal direction) we can apply: Here R stands for the masses which are moving towards right and L for the masses towards left, x is displacement, v is velocity and a the acceleration (all with respect to ground). A small block of mass m = 1 kg is placed over a wedge of mass M = 4 kg as shown in figure. Mass m is released from rest. All surfaces are smooth. Origin O is as shown. At the same instant reaction on the wedge from the ground is N
If net force on a system in a particular direction is zero (say in horizontal direction) we can apply: Here R stands for the masses which are moving towards right and L for the masses towards left, x is displacement, v is velocity and a the acceleration (all with respect to ground). A small block of mass m = 1 kg is placed over a wedge of mass M = 4 kg as shown in figure. Mass m is released from rest. All surfaces are smooth. Origin O is as shown. At the same instant reaction on the wedge from the ground is N
physics-General
physics-
If net force on a system in a particular direction is zero (say in horizontal direction) we can apply: Here R stands for the masses which are moving towards right and L for the masses towards left, x is displacement, v is velocity and a the acceleration (all with respect to ground). A small block of mass m = 1 kg is placed over a wedge of mass M = 4 kg as shown in figure. Mass m is released from rest. All surfaces are smooth. Origin O is as shown. Normal reaction between the two blocks at an instant when absolute acceleration of m is m/s2 at 60° with horizontal is N. Normal reaction at this instant is making with horizontal:
If net force on a system in a particular direction is zero (say in horizontal direction) we can apply: Here R stands for the masses which are moving towards right and L for the masses towards left, x is displacement, v is velocity and a the acceleration (all with respect to ground). A small block of mass m = 1 kg is placed over a wedge of mass M = 4 kg as shown in figure. Mass m is released from rest. All surfaces are smooth. Origin O is as shown. Normal reaction between the two blocks at an instant when absolute acceleration of m is m/s2 at 60° with horizontal is N. Normal reaction at this instant is making with horizontal:
physics-General
physics-
If net force on a system in a particular direction is zero (say in horizontal direction) we can apply: Here R stands for the masses which are moving towards right and L for the masses towards left, x is displacement, v is velocity and a the acceleration (all with respect to ground). A small block of mass m = 1 kg is placed over a wedge of mass M = 4 kg as shown in figure. Mass m is released from rest. All surfaces are smooth. Origin O is as shown. The block will strike the x–axis at x = ....m :–
If net force on a system in a particular direction is zero (say in horizontal direction) we can apply: Here R stands for the masses which are moving towards right and L for the masses towards left, x is displacement, v is velocity and a the acceleration (all with respect to ground). A small block of mass m = 1 kg is placed over a wedge of mass M = 4 kg as shown in figure. Mass m is released from rest. All surfaces are smooth. Origin O is as shown. The block will strike the x–axis at x = ....m :–
physics-General
physics-
If net force on a system in a particular direction is zero (say in horizontal direction) we can apply: Here R stands for the masses which are moving towards right and L for the masses towards left, x is displacement, v is velocity and a the acceleration (all with respect to ground). A small block of mass m = 1 kg is placed over a wedge of mass M = 4 kg as shown in figure. Mass m is released from rest. All surfaces are smooth. Origin O is as shown. Final velocity of the wedge is m/s :–
If net force on a system in a particular direction is zero (say in horizontal direction) we can apply: Here R stands for the masses which are moving towards right and L for the masses towards left, x is displacement, v is velocity and a the acceleration (all with respect to ground). A small block of mass m = 1 kg is placed over a wedge of mass M = 4 kg as shown in figure. Mass m is released from rest. All surfaces are smooth. Origin O is as shown. Final velocity of the wedge is m/s :–
physics-General
physics-
When two bodies collide normally, they exert equal and opposite impulses on each other. Impulse = change in linear momentum. Coefficient of restitution between two bodies is given by :– for elastic collision Two bodies collide as shown in figure. During collision they exert impulse of magnitude J on each other. For what values of J (in N–s) the 2 kg block will change its direction of velocity :
When two bodies collide normally, they exert equal and opposite impulses on each other. Impulse = change in linear momentum. Coefficient of restitution between two bodies is given by :– for elastic collision Two bodies collide as shown in figure. During collision they exert impulse of magnitude J on each other. For what values of J (in N–s) the 2 kg block will change its direction of velocity :
physics-General
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When two bodies collide normally, they exert equal and opposite impulses on each other. Impulse = change in linear momentum. Coefficient of restitution between two bodies is given by :– for elastic collision Two bodies collide as shown in figure. During collision they exert impulse of magnitude J on each other. If the collision is elastic, the value of J is N–s :
When two bodies collide normally, they exert equal and opposite impulses on each other. Impulse = change in linear momentum. Coefficient of restitution between two bodies is given by :– for elastic collision Two bodies collide as shown in figure. During collision they exert impulse of magnitude J on each other. If the collision is elastic, the value of J is N–s :
physics-General
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A police car moving at, changes a motorcyclist. The police man sounds his horn at 176 Hz, while both of them move towards a stationary siren of frequency 165 Hz. Calculate the speed of the motorcycle, if it is given that he does not observe any beats.
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physics-General
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Figure here shown an incident pulse reflected from a rigid support. Which one of represents the reflected pulse correctly
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physics-General
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The tangent at the point P(x1, y1) to the parabola y2 = 4ax meets the parabola y2 = 4a(x + b) at Q and R, the coordinates of the mid-point of QR are
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maths-General
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If P (t2, 2t) t [0, 2] is an arbitrary point on parabola y2 = 4x. Q is foot of perpendicular from focus S on the tangent at P, then maximum area of PQS is-
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maths-General