Physics-
General
Easy

Question

When the mass of a system is variable, a thrust force has to be applied on it in addition to all other forces acting on it. This thrust force is given by stack F with rightwards arrow on top equals stack v with rightwards arrow on top subscript r end subscript open parentheses plus-or-minus fraction numerator d m over denominator d t end fraction close parentheses Here stack v with rightwards arrow on top subscript r end subscriptis the relative velocity with which the mass d m either enters or leaves the system. A car has total mass 50 kg. Gases are ejected from this backwards with relative velocity 20 m/s. The rate of ejection of gas is 2 kg/total mass of gas is 20 kg. Coefficient of friction between the car and road is mu = 0.1 Car will start moving after time t = . .. second:

  1. 4    
  2. 10    
  3. 5    
  4. 8    

The correct answer is: 10

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In an oblique collision component parallel to common tangent remains unchanged while along common normal direction, relative velocity of separation becomes e times the relative velocity of approach. A ball collides at B with velocity 10 m/s at 30° with vertical. There is a flag at A and a wall at C. Collision of ball with ground is perfectly inelastic (e = 0) and that with wall is elastic (e = 1). Given AB = BC = 10m. The ball will collide with the flag after time t = ....s

In an oblique collision component parallel to common tangent remains unchanged while along common normal direction, relative velocity of separation becomes e times the relative velocity of approach. A ball collides at B with velocity 10 m/s at 30° with vertical. There is a flag at A and a wall at C. Collision of ball with ground is perfectly inelastic (e = 0) and that with wall is elastic (e = 1). Given AB = BC = 10m. The ball will collide with the flag after time t = ....s

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If net force on a system in a particular direction is zero (say in horizontal direction) we can apply: sum m subscript R end subscript x subscript R end subscript equals sum m subscript L end subscript x subscript L end subscript comma sum m subscript R end subscript v subscript R end subscript equals sum m subscript L end subscript v subscript L end subscript text  and  end text sum m subscript R end subscript a subscript R end subscript equals sum m subscript L end subscript a subscript L end subscript Here R stands for the masses which are moving towards right and L for the masses towards left, x is displacement, v is velocity and a the acceleration (all with respect to ground). A small block of mass m = 1 kg is placed over a wedge of mass M = 4 kg as shown in figure. Mass m is released from rest. All surfaces are smooth. Origin O is as shown. At the same instant reaction on the wedge from the ground is N

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If net force on a system in a particular direction is zero (say in horizontal direction) we can apply: sum m subscript R end subscript x subscript R end subscript equals sum m subscript L end subscript x subscript L end subscript comma sum m subscript R end subscript v subscript R end subscript equals sum m subscript L end subscript v subscript L end subscript text  and  end text sum m subscript R end subscript a subscript R end subscript equals sum m subscript L end subscript a subscript L end subscript Here R stands for the masses which are moving towards right and L for the masses towards left, x is displacement, v is velocity and a the acceleration (all with respect to ground). A small block of mass m = 1 kg is placed over a wedge of mass M = 4 kg as shown in figure. Mass m is released from rest. All surfaces are smooth. Origin O is as shown. Normal reaction between the two blocks at an instant when absolute acceleration of m is 5 square root of 3 m/s2 at 60° with horizontal is N. Normal reaction at this instant is making 30 to the power of ring operator end exponent with horizontal:

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